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Vesnalui [34]
3 years ago
8

Christian sold tickets to the game . Good seats were $5 each and poor seats cost $2 each. 210 people attended and paid $660. How

many of each type of seat were sold
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
People who purchased good seats will be labeled as a
people who purchased poor seats will be labeled as b
therefore...
5a + 2b = 660
a + b = 210
Now, all that has to be done is for the system to be solved.
-2(a+b=210)

5a + 2b = 660
-2a - 2a = -420

3a=240
a= 80
*3 people purchased good seats.

Now we can plug that number in

5(80) + 2b = 660
400 + 2b = 660
2b = 260
b = 130
*130 people purchased poor seats

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