Answer:
<h2>$200</h2>
Step-by-step explanation:
This question has some missing information, here is a complete one
Pat and Kamal had $575 altogether. Pat spent 3/5 of her money and Kamal spent $150. Pat then had three times as much money as Kamal. How much did Kamal have at first.
you can find attached a detailed solution of the question for your reference
60/48
Both can be reduced by 12 to 5/4
So you can have 12 groups with 5 6th graders and 4 7th graders
A.) m + s = 325
45m + 20s = 12,000
b.) 220 people attended main stage
c.) 105 people attended second stage
How you figure this out:
You can first find the value of (s) by using m + s = 325 and subtracting m from both sides. This leaves you with s = -m + 325 as the value of s. Now substitute that into the equation 45m + 20s = 12,000 and you should have something like this -> 45m + 20 (-m + 325) = 12,000 Now distribute the 20 to both (-m) and (325) which then leaves you with this -> 45m - 20m + 6,500 = 12,000
Next thing you would do is combine like terms which in the case is 45m and -20m. Now combine those term to get -> 25m + 6,500 = 12,000 Now you would subtract 6,500 from both sides and then that would leave you with this -> 25m = 5,500 Lastly divide 25 into both sides to get your solution for m, m = 220. Now that you know the value of (m), substitute it into the equation M + S = 325 and it would look like this -> 220 + s = 325 now you would subtract 220 from both sides to get your solution for s, s = 105
I really hope this helps and let me know if you have any questions! :)
The correct answer: −18y−40
10 groups of 3 students = 30
3 groups of 10 students = 30
5 groups of 6 students = 30
6 groups of 5 students = 30
2 groups of 15 students = 30
15 groups of 2 students = 30
