Answer:
A .cos(x)<1
Step-by-step explanation:
According to the first inequality
cos(x)<1
x < arccos 1
x<0
This therefore does not have a solution within the range 0 ≤ x ≤ 2pi
x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.
For the second option
.cos(x/2)<1
x/2< arccos1
x/2<0
x<0
This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.
For the inequality csc(x)<1
1/sin(x) < 1
1< sin(x)
sinx>1
x>arcsin1
x>90°
x>π/2
This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values
For the inequality csc(x/2)<1
1/sin(x/2) < 1
1< sin(x/2)
sin(x/2)> 1
x/2 > arcsin1
X/2 > 90°
x>180°
x>π
This value of x also has a solution within the range.
Therefore option A is the only inequality that does not have a solution with the range.
Answer:
x=5
Step-by-step explanation:
(8x-8)3/2=64
(24x-8)/2=64 -You are distributing the three
12x-4=64 -You divide the whole thing by two
12x=60 -You subtract the four from both sides
x=5 - You divided the twelve from both sides
Hope this helps!
Answer:
What is the question?
Step-by-step explanation:
1. Write all of the question to receive a correct answer.
11:100
iwan:siobhan
if iwan gets 11% then iwan gets 89/100
