This question was not written properly
Complete Question
Find the minimum value of the function f(x) = 0.9x² + 3.42x - 2.4 to the nearest
hundredth.
Answer:
The minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
Step-by-step explanation:
Our quadratic equation =
ax² + bx + c
f(x) = 0.9x² + 3.42x - 2.4
The minimum value of x formula=
x = -b/2a
a = 0.9
b = 3.42
x = -3.42/2 × 0.9
x = -3.42/1.8
x = -1.9
We input the value x in order to get the minimum value of y
f(x) = y
f(x) = 0.9x² + 3.42x - 2.4
f(-1.9) = 0.9(-1.9)² + 3.42(-1.9) - 2.4
= 3.249 - 6.498 - 2.4
=3.249 - 8.898
= -5.649
Approximately to the nearest hundredth = -5.65
Therefore, the minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
Answer:
B. Since Ax-b is consistent, its solution set is obtained by translating the solution set of Ax=0. So the solution set of Ax = b is a single vector if and only if the solution set of Ax= 0 is a single vector, and that happens if and only if Ax 0 has only the trivial solution.
Step-by-step explanation:
the answer to the question is answer B. and here is the explanation below
let us imagine that the equation ax = b has a solution
now our goal will be to show that the solution of ax =b when ax = 0 has only trivial solution.
ax = 0 is homogenous
if this equation was consistent for b, we define
ax = b to be a set of vector that has the form
w = m + gh(h is a subscript)
gh is a solution of ax = 0
from what we have above, ax=b is in the form ofw= m+gh
with
m = solution of ax=b
gh = soulution of ax=0
ax = 0 has only trivial solution
gh = 0
with gh = 0
ax=b is w=m
so ax = b is unique.
Answer:
- They can be used for quantitative data
- They can be used for qualitative data.
- No observation can fit into more than one class
Step-by-step explanation:
- The frequency table refers to the number of times the event occurs and lists the items shown by value and thus is quantitative and qualitative such as graphs and numerical summary.
Answer:
see below
Step-by-step explanation:
In order to use ASA congruence, you need to show congruence of angles on either side of a congruent segment. (Angle - Side - Angle) Considering the left side of the figure, you have given that ∠B is congruent to its counterpart, side BC is congruent to its counterpart. So, you need to show the angle at C is congruent to its counterpart. That is, you must show ...
∠BCA ≅ ∠DCE
Answer:
5.33333.....
Step-by-step explanation:
I used symbolab to get my answer make me brainleist pls
