Which expression is equivalent to x^2 • x^3? A- x^5 B- x^-1 C- x^6 D- 6 x 5

baseten school district bought 5,000 pencils. they are distributing the pencils evenly to 10 school in the district . how many p

andrew11 [14]

Answer:

500

Step-by-step explanation:

5000 divided by 10

3 0

2 years ago

Big burger is offering a value meal that includes a burger, and two side items such as fries, salad or drink. each if the side i

Marina CMI [18]

Answer:

2 1/2 dollars per side

Step-by-step explanation:

7 + 5 is 12 so half of five ( 5$ is the price of two sides ) is 2 1/2 and 2 1/2 is the price of one side.

( sorry if it is confusing ^O^ )

5 0

2 years ago

What is the value of x in the equation shown below 0.75x + 3 = 6(x - 3)

EleoNora [17]

Answer: x=4

Step-by-step explanation: 0.75x+3=6(x−3)

0.75x+3=(6)(x)+(6)(−3)

0.75x+3=6x+−18

0.75x+3=6x−18

0.75x+3−6x=6x−18−6x

−5.25x+3−3=−18−3

−5.25x /−5.25 =− 21 /−5.25

x=4

7 0

2 years ago

Rosario and Enrqiue are in the same mathematics

Paul [167]

Answer:Enrqiue's average was higher than Rosario's average by 3

Step-by-step explanation:

Rosario's average= sum of 78, 77, 64, 86, and 70/ no of scores= 375/5= 75

Enrique's average=sum of 90, 61, 79, 73, and 87/ no of scores = 390/5=78

78-75=3

3 0

3 years ago

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m

Flauer [41]

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

semiperimeter: p = (51+37+20):2 = 54 m

Area of triangle:

$A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2$

Rate: ₹ 3 per m².

Cost: ₹ 3•306 = ₹ 918

2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm

p = 11:2 = 5.5

$A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2$

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

p = (8•3):2 = 12 cm

$A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2$

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

b = 3x

2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm

p = 32:2 = 16 cm

$A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2$

8 0

2 years ago