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3 years ago

8

,,,,,....,,,,,:;,,,,,:(

1 answer:

pshichka [43]3 years ago

8 0

start at -2 go over 2 and up 5

(-2, 5)

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A hiker averages 1.4 mph downhill on a mountain trail and 0.8 mph uphill. Find the total time spent hiking in terms of the dista

nadya68 [22]

Answer:

V=d/t.

V=(1.4)(0.8)÷8m/s

=0.14

Step-by-step explanation:

bali yung divide ay guhit sa baba

3 0

3 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

2 years ago

A javelin thrower is running at 7mph and throws her javelin at 18mph at an angle of 13o with the horizontal. Determine the resul

RUDIKE [14]

Will I get any points?

5 0

2 years ago

Find the Area of the figure below, composed of a rectangle and a semicircle.

Mamont248 [21]

Answer:

68.1 units²

Step-by-step explanation:

Start by finding the area of the rectangle...

$Area=lw\\Area=6*9\\Area=54$

Then, find the area of the semicircle...

$Radius=\frac{1}{2}*Diameter=\frac{1}{2}*6=3$

$Area=\frac{1}{2}\pi r^2\\Area=\frac{1}{2}\pi 3^2\\Area=\frac{1}{2}\pi 9\\Area=\frac{9}{2}\ pi\\Area\approx14.1$

Now, add the two to get...

54+14.1=68.1

3 0

2 years ago

What is the value of f(x)=-4 ?

Gala2k [10]

Answer : 2

Step by step walkthrough:

7 0

3 years ago