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3 years ago

,,,,,....,,,,,:;,,,,,:(

Mathematics

1 answer:

pshichka [43]3 years ago

8 0

start at -2 go over 2 and up 5

(-2, 5)

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Determine the image of the given point under the indicated reflection.

Aleks04 [339]

(-2,-8) is what I got after reflecting it off the y=x line.

6 0

3 years ago

How do you solve this (−18) ÷ 3 + (5)(−2) ?

Alekssandra [29.7K]

<span>(−18) ÷ 3 + (5)(−2)
Multiply 5 by -2
(-18)/3 -10
Divide -18 by 3
-5-10
Subtract 10 from -5
Final Answer: -15</span>

6 0

3 years ago

I dont understand please help

DiKsa [7]

$2 \frac{1}{2}+(-2\frac{1}{4})$

This is equal to:

$2\frac{1}{2}-2\frac{1}{4}$

When you add a negative number, it turns into subtraction.

First, I would change it to mixed numbers:

$\frac{5}{2}-\frac{9}{4}$

Now, you need to change the denominators to make sure they are the same on both fractions. I changed the first fraction's denominator to 4 so they match. You can do this by multiplying the numerator by 2:

$\frac{10}{4}-\frac{9}{4}$

Now, you simply subtract:

10-9=1

1/4 is your answer.

I hope this helps :)

3 0

3 years ago

To find out how fast a tree grows, you can measure its trunk. A giant red oak's diameter was 248 inches in 1965. The tree's diam

Semmy [17]

You need to find the slope
251-248. 3
------------- = --------
2005-1965. 40

5 0

3 years ago

Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number

Triss [41]

Answer:

By definition, the derivative of f(x) is

$lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

Let's use the definition for $f(x)=\frac{1}{x}$

$lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}$

Then, $f'(x)=\frac{-1}{x^2}$

7 0

3 years ago