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weeeeeb [17]
3 years ago
5

Is this answer right?

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

0

Step-by-step explanation:

(15 - 6)^{2}  \div 3 -  {3}^{3}  =  {9}^{2}  \div  3 - 27 = 81 \div 3 - 27 = \\  \\ 27 - 27 = 0

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], evaluate everything in grouping symbols first, then exponents [indices, roots, etcetera], Division & Multiplication from left to right, then Subtraction & Addition from right to left [or left to right as you know what you are doing correctly].

I am joyous to assist you anytime.

lubasha [3.4K]3 years ago
5 0

Solve using the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

REMEMBER: IF NOT APPLICABLE TO THE EQUATION YOU MAY SKIP THAT STEP IN PEMDAS .

3(8 - 2) + 4 = 22

Parentheses...

(15 - 6)² ÷ 3 - 3³

15 - 6 = 9

(9)² ÷ 3 - 3³

Exponent....

9² ÷ 3 - 3³

In this case you have two exponents. Always apply the steps from left to right

9² ÷ 3 - 3³

9² = 81

81 ÷ 3 - 3³

3³ = 27

81 ÷ 3 - 27

Division...

81 ÷ 3 - 27

81 ÷ 3 = 27

27 - 27

Subtraction...

27 - 27 = 0

0

<u>Your mistake: </u>

You subtracted 3 - 27 before dividing 81 by 3. Remember that according to the rules of PEMDAS division must come before subtraction

Hope this helped!

~Just a girl in love with Shawn Mendes

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Nuetrik [128]

Answer:

The answer is =  112

Step-by-step explanation:

3x4 = 12

12 - 2 = 10

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4 0
3 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
The graph of this function is shifted 7 units right and shifted 5 units up.
mojhsa [17]
<h2><u>Graphing</u></h2>

<h3>The graph of this function is shifted 7 units right and shifted 5 units up.</h3>

<h3>f(x) = -2/3(x - 7)² - 5</h3>

  • True
  • False

<u>Answer:</u>

  • <u>False</u>

<u>Explanation:</u>

  • Why false? As I noticed, in the equation f(x) = -2/3(x - 7)² - 5, the vertex is (7, -5). The value of a, which is -2/3, is negative. So the graph opens downwards. The graph shifts 7 units to the right, which is correct, but graphing 5 units up is wrong. Why? 5 is negative, so it should be shifted 5 units down.

Wxndy~~

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kozerog [31]

144 classes. each class is 10 minutes. 6X24= 144

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