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weeeeeb [17]
3 years ago
5

Is this answer right?

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

0

Step-by-step explanation:

(15 - 6)^{2}  \div 3 -  {3}^{3}  =  {9}^{2}  \div  3 - 27 = 81 \div 3 - 27 = \\  \\ 27 - 27 = 0

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], evaluate everything in grouping symbols first, then exponents [indices, roots, etcetera], Division & Multiplication from left to right, then Subtraction & Addition from right to left [or left to right as you know what you are doing correctly].

I am joyous to assist you anytime.

lubasha [3.4K]3 years ago
5 0

Solve using the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

REMEMBER: IF NOT APPLICABLE TO THE EQUATION YOU MAY SKIP THAT STEP IN PEMDAS .

3(8 - 2) + 4 = 22

Parentheses...

(15 - 6)² ÷ 3 - 3³

15 - 6 = 9

(9)² ÷ 3 - 3³

Exponent....

9² ÷ 3 - 3³

In this case you have two exponents. Always apply the steps from left to right

9² ÷ 3 - 3³

9² = 81

81 ÷ 3 - 3³

3³ = 27

81 ÷ 3 - 27

Division...

81 ÷ 3 - 27

81 ÷ 3 = 27

27 - 27

Subtraction...

27 - 27 = 0

0

<u>Your mistake: </u>

You subtracted 3 - 27 before dividing 81 by 3. Remember that according to the rules of PEMDAS division must come before subtraction

Hope this helped!

~Just a girl in love with Shawn Mendes

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Answer:

An arrow diagram

Step-by-step explanation:

Helps keep track of intricate relationships between variables. Specifies the phenomena of interest: independent, alternative, antecedent and intervening.

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3 years ago
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JulsSmile [24]

Answer:

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y = a(x-h)2 + k            standard form

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y = 5(x-0)2 - 4            re-written in standard form

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Step-by-step explanation:

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Answer as a compound inequality: -4 \le y < 2

Answer in interval notation:  [-4, 2)

=============================================

Explanation:

The range is the set of all possible y outputs of a function. When dealing with a graph like this, we just look at the highest and lowest points to determine which y values are possible.

The lowest point occurs when y = -4. We include this value. So far we have y \ge -4 which is the same as -4 \le y

The upper ceiling for the y value is y = 2. We can't actually reach this value because of the open hole at (-3,2). So we say that y < 2

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To convert this to interval notation, we write [-4, 2) where the square bracket says to include the endpoint and the curved parenthesis says to exclude the endpoint.

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