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3 years ago

Determine the scale factor for this scale diagram. Is it an enlargement or reduction?

Mathematics

1 answer:

kupik [55]3 years ago

4 0

Answer:

d. C. 4; enlargement

Step-by-step explanation:

Scale factor = Ratio of one of the side length of the scale diagram to the corresponding side length of the original diagram

Side length of scale diagram = 8 units

Corresponding side length of original diagram = 2 units

Thus:

Scale factor = 8/2 = 4

Scale factor = 4

Since it's an while number, it implies that it is an enlargement.

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What is the inverse operation of 2/3x=6

Artemon [7]

2 3 x - 6

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=3x2+9 f - 1 ( x ) = 3 x 2 + 9 is the inverse of f(x)=23x−6 f ( x ) = 2 3 x - 6

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3 years ago

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d1i1m1o1n [39]

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2 years ago

Translation of the length of a rectangle is 2 feet greater than twice its width. If the perimeter is 25 feet, fine the width

blsea [12.9K]

Answer:

Step-by-step explanation:

Perimeter of a rectangle=(length+width)×2

Let W=x, L=2x+2

25=[(2x+2)+x]×2

25=[2x+2+x]×2

Solve for x

25/2=3x+2

25/2-2=3x

25-4/2=3x

21\2=3x=7/2=x

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3 years ago

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

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3 years ago

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Vera_Pavlovna [14]

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The left end approaches positive infinity and the right end approaches zero.

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3 years ago