Answer:
6x - 11y = -13 is the answer.
Step-by-step explanation:
Let's plug in the points to see what sticks.
Start with (-4, -1)
1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 
13
2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 17
4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 13
The only one that fits is #2. Let's try the other point to be sure.
2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13
Lets look at the number. 76.78. In each of the different place holders the number is higher than 5. Lets do some examples. 74 rounded to the nearest whole number is going to be 70. 76 rounded to the whole number will be 80. The .78 in your question also contributes.
Answer: 80
Answer: 5 benches and 23 students
Step-by-step explanation:
I will answer in English.
We have E students and B benches.
If we sit 4 students per bench, we have 3 students left.
then:
E = 4*B + 3
And if we sit 5 students per bench, there are two places with no students sited.
E = 5*B - 2
now we can replace the E in the second equation with the right part in the first equation:
4*B + 3 = 5*B - 2
3 + 2 = 5*B - 4*B
5 = B
So we have 5 benches, and:
E = 4*5 + 3 = 23 students.
Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample 
= 31.2 pounds .
Step-by-step explanation:
The weights of spawning Chinook salmon in the Columbia river are normally distributed.
Given : The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.
The point estimate for the mean 
weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]
