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Aleksandr-060686 [28]
2 years ago
7

What are the answers to the equation please get back to me

Mathematics
1 answer:
Keith_Richards [23]2 years ago
4 0

Answer:

A

Step-by-step explanation:

Since you are multiplying -2 and 12, you can put them in any order as long as you get - 24/5

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Information about the students at Jackson High School is shown in the table.
SSSSS [86.1K]

Answer:

A or Out of the 352 eleventh graders at the school, 173 of them are girls

Step-by-step explanation:

cause i did it  and your welcome to all the poor souls in

5 0
3 years ago
Read 2 more answers
What is the best way to describe the solution of this system of equations?
fomenos
The answer for this problems is D. because the y-intercept is 4 for both equations.
please like and rate.
plus u can find the answer in math-way ;).
3 0
3 years ago
Which of the following is the missing reason? Statements Reasons two thirds times x plus 7 equals negative 5 Given 2x 21 = â’15
pentagon [3]

The correct option is B. Distributive property

Given,

\frac{2}{3} x+7=-5\\

On solving the above equation,

multiplying both sides by 3 we, get

2x+21=-15

now subtracting 21 from both the sides,

2x=-36\\

dividing both the sides by 2 we get,

x=-18

Since in the above steps we follow all the giving property except the distributive property.

Hence the correct option is B. Distributive property.

For more details follow the link:

brainly.com/question/13130806

6 0
2 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
1st. (2 root 2 + root 3 ) ( 2 root 3 - root 2)
satela [25.4K]

Answer:

1st: 3*root6 + 5

2nd: 35*root2 + 115

3rd: 24*root2 - 20*root6 + 15*root3 - 18

4th: 17*root6 - 38

5th: 13*root10 - 42

Step-by-step explanation:

To simplify these expressions we need to use the distributive property:

(a + b) * (c + d) = ac + ad + bc + bd

So simplifying each expression, we have:

1st.

(2 root 2 + root 3 ) ( 2 root 3 - root 2)

= 4*root6 - 2*2 + 2*3 - root6

= 3*root6 - 4 + 9

= 3*root6 + 5

2nd.

(root 5 + 2 root 10) (3 root 5 + root 10)

= 3 * 5 + root50 + 6*root50 + 2*10

= 15 + 5*root2 + 30*root2 + 100

= 35*root2 + 115

3rd.

(4 root 6 - 3 root 3) (2 root 3 - 5)

= 8*root18 - 20*root6 - 6*3 + 15root3

= 24*root2 - 20*root6 + 15*root3 - 18

4rd.

(6 root 3 - 5 root 2 ) (2 root 2 - root 3)

= 12*root6 - 6*3 - 10*2 + 5*root6

= 17*root6 - 18 - 20

= 17*root6 - 38

5th.

(root 10 - 3 ) ( 4 - 3 root 10)

= 4*root10 - 3*10 - 12 + 9*root10

= 13*root10 - 30 - 12

= 13*root10 - 42

8 0
2 years ago
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