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Gnesinka [82]
3 years ago
14

The structure of a two-factor study can be presented as a matrix with the levels of one factor determining the rows and the leve

ls of the second factor determining the columns. With this structure in mind, describe the mean differences and interactions between factors that are evaluated by each of the three hypothesis tests that make up a two-factor ANOVA.
Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

Following are the solution to this question:

Step-by-step explanation:

It provides three different hypotheses in such a two-factor ANOVA:  

In point A:

H o: With all factor A levels, the ways are equivalent  

Ha: A least another element A level does have a transfer to another

In point B:

Ha: The least one Factor A the level does have a transfer to another

H o: With all Factor B levels the results are about the same.

In point C:

Ha: At most one Variable B level does have a transfer than any other level.

H o: There are no interactions among the factors

Ha: The interactions of factors are important

When ANOVA is executed, they get three p-sets (one for all 3 hypotheses)

(a) If Variable A's p-value is much less alpha, we will reject the null and embrace Ha and infer that Factor A is important. Anything else, H o also isn't rejected and that there is no evidence which Factor A is important

(b) If p- is < alpha, otherwise we reject The null, accept Ha, and infer which Factor B is relevant. Factor B is significant. Conversely, we may not condemn H o but claim there isn't enough proof which Factor B is important

(c)

If they reject H o and agree to the point p- for the A x B interaction is a < alpha Ha, and conclude that the interaction from A to B is important. So, perhaps we can deny H o and claim, that neither proof of interactions is sufficient From A to B.

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Answer:

z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

z=r(\cos \theta +i\sin \theta)

where, r=\sqrt{a^2+b^2} and \tan \theta=\dfrac{b}{a}, \theta is called the argument of z, 0\leq \theta\leq 2\pi.

The given complex number is -5i.

It can be rewritten as

z=0-5i

Here, a=0 and b=-5. \theta lies in 4th quadrant.

r=\sqrt{0^2+(-5)^2}=5

\tan \theta=\dfrac{-5}{0}

\tan \theta=\infty

\theta=2\pi -\dfrac{\pi}{2}    [\because \text{In 4th quadrant }\theta=2\pi-\theta]

\theta=\dfrac{3\pi}{2}

So, the trigonometric form is

z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)

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3 years ago
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Answer:

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Step-by-step explanation:

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Of the population of all fruit flies we wish to give a 90% confidence interval for the fraction which possess a gene which gives
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Answer:

The margin of error for the 90% confidence interval is of 0.038.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

To this end we have obtained a random sample of 400 fruit flies. We find that 280 of the flies in the sample possess the gene.

This means that n = 400, \pi = \frac{280}{400} = 0.7

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Give the margin of error for the 90% confidence interval.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.645\sqrt{\frac{0.7*0.3}{400}}

M = 0.038

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Answer:

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