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Gnesinka [82]
3 years ago
14

The structure of a two-factor study can be presented as a matrix with the levels of one factor determining the rows and the leve

ls of the second factor determining the columns. With this structure in mind, describe the mean differences and interactions between factors that are evaluated by each of the three hypothesis tests that make up a two-factor ANOVA.
Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

Following are the solution to this question:

Step-by-step explanation:

It provides three different hypotheses in such a two-factor ANOVA:  

In point A:

H o: With all factor A levels, the ways are equivalent  

Ha: A least another element A level does have a transfer to another

In point B:

Ha: The least one Factor A the level does have a transfer to another

H o: With all Factor B levels the results are about the same.

In point C:

Ha: At most one Variable B level does have a transfer than any other level.

H o: There are no interactions among the factors

Ha: The interactions of factors are important

When ANOVA is executed, they get three p-sets (one for all 3 hypotheses)

(a) If Variable A's p-value is much less alpha, we will reject the null and embrace Ha and infer that Factor A is important. Anything else, H o also isn't rejected and that there is no evidence which Factor A is important

(b) If p- is < alpha, otherwise we reject The null, accept Ha, and infer which Factor B is relevant. Factor B is significant. Conversely, we may not condemn H o but claim there isn't enough proof which Factor B is important

(c)

If they reject H o and agree to the point p- for the A x B interaction is a < alpha Ha, and conclude that the interaction from A to B is important. So, perhaps we can deny H o and claim, that neither proof of interactions is sufficient From A to B.

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Elina [12.6K]

Answer:

Archimedes was the first to derive this formula.

Step-by-step explanation:


7 0
3 years ago
Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360° ​
vodka [1.7K]

2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x  -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or}  ~~u =\dfrac{-4}{4} =-1\\\\

\implies \tan x = \dfrac 12 ~~ \text{or} ~~  \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\

x=\tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,}   ~~x=\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\

\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]

4 0
2 years ago
An attic floor is shaped like a triangle with a height of n yd and a base of 6 yd. Which expression represents the area of the f
Gwar [14]
I think it is 2..... i am not really sure
7 0
3 years ago
I need some help with this
masya89 [10]

Answer:

A, C, D

Step-by-step explanation:

Consider triangles NKL and NML. These triangles are right triangles, because

m\angle K=m\angle M=90^{\circ}

In these right triangles:

  • \overline{NL}\cong \overline {NL} - reflexive property;
  • \angle KLN\cong \angle MLN - given

Thus, triangles NKL and NML by HA postulate. Congruent triangles have congruent corresponding parts, so

\overline{KN}\cong \overline{NM}\\ \\\overline{KL}\cong \overline{LM}\ [\text{option D is true}]

Since

\overline{KN}\cong \overline{NM},

then

7x-4=5x+12\\ \\7x-5x=12+4\\ \\2x=16\\ \\x=8\ [\text{option A is true}]\\ \\MN=KN=7\cdot 8-4=56-4=52\ [\text{option C is true}]

Option B is false, because KN=52 units.

Option E is false, because LN is congruent KN, not LM

4 0
3 years ago
Your teacher asked you to represent 3 more than 8 multiplied by a number t as an expression. You wrote 3 + 8t, and your friend w
Leni [432]

Both answers are not the same. You are correct and your friend is wrong. The situation your teacher gave could have only one other interpretation that would be acceptable and that would be 8t+3 because it is the same number just in a different order.

3 0
3 years ago
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