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Strike441 [17]
3 years ago
13

Find the range for the projectiles with the following speeds and angles:

Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:

129.78m

Explanation:

The following data were obtained from the question:

θ = 16.9°

U = 48.3m/s

g = 10m/s2

R =?

R = U^2 Sin2θ / g

R = (48.3)^2 Sin33. 8/ 10

R = 129.78m

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A ball is projected upward at time t=0.0s, from a point on a roof 90m above the ground. The ball rises, then falls and strikes t
chubhunter [2.5K]
As v becomes zero at the highest point, i prefer considering different travelling directions so it will become less complicated.
dont forget to add the total time up .

also to master the skills, write down the "uvsat" may help (thats the way i found it easier to handle problems)

4 0
3 years ago
the speed of a tortoise and a hare are 1m/s and 3m/s. the mass of hare is 5kg and the tortoise is 20kg. which has greater moment
Novosadov [1.4K]

Answer: tortoise

Explanation:

Given the following :

Speed of tortoise = 1m/s

Speed of hare = 3m/s

Mass of hare = 5kg

Mass of tortoise = 20kg

Momentum = product of Mass and velocity

Momentum of hare = mass of hare × Velocity of hare

Momentum of hare = 5kg × 3m/s = 15kgm/s

Momentum of tortoise = mass of tortoise × Velocity of tortoise

Momentum of tortoise = 20kg × 1m/s = 20kgm/s

Therefore, tortoise has a greater momentum than hare.

8 0
3 years ago
Question :
Alex73 [517]

Answer: Newton's third law simply states that for every action there is an equal and opposite reaction. So, if object A acts a force upon object B, then object B will exert an opposite yet equal force upon object A

5 0
2 years ago
10 The magnitude J of the current density in a certain lab wire with a circular cross section of radius R = 2.00 mm is given by
rewona [7]

Answer:

I = 0.002593 A = 2.593 mA

Explanation:

Current density = J = (3.00 × 10⁸)r² = Br²

B = (3.00 × 10⁸) (for ease of calculations)

The current through outer section is given by

I = ∫ J dA

The elemental Area for the wire,

dA = 2πr dr

I = ∫ Br² (2πr dr)

I = ∫ 2Bπ r³ dr

I = 2Bπ ∫ r³ dr

I = 2Bπ [r⁴/4] (evaluating this integral from r = 0.900R to r = R]

I = (Bπ/2) [R⁴ - (0.9R)⁴]

I = (Bπ/2) [R⁴ - 0.6561R⁴]

I = (Bπ/2) (0.3439R⁴)

I = (Bπ) (0.17195R⁴)

Recall B = (3.00 × 10⁸)

R = 2.00 mm = 0.002 m

I = (3.00 × 10⁸ × π) [0.17195 × (0.002⁴)]

I = 0.0025929449 A = 0.002593 A = 2.593 mA

Hope this Helps!!!

4 0
3 years ago
Which disadvantage of nuclear power use poses the greatest threat to the environment?
Mekhanik [1.2K]

The correct answer is The storage and management of radioactive wastes

Explanation:

In general, nuclear reactions (changes in the nucleus of an atom such as fission) release a lot of energy including a lot of heat. Moreover, this heat is used by humans to obtain electricity and other types of energy, which is known as a nuclear power. This type of power is considered positive because it does not emit carbon and it is quite efficient.

However, in most cases, it is a threat to the environment and living beings because storing and managing the wastes of this type of power is difficult and expensive. Indeed, dealing with the wastes of nuclear power requires complex infrastructure, and any accident or leaking leads to serious consequences from the death of those exposed to the wastes to permanent loss of diversity or changes in nearby areas.

6 0
3 years ago
Read 2 more answers
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