Answer:
d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih
Answer:
1. Torque → F. Study of forces
2. C.O.G → D. Point of action of weight.
3. Plumb line → A. Line of C.O.G
Answer: 200 J
Explanation: In order to explain this we have consider that the work done in a electric field is given by:
Work= Q*ΔV=2*100=200J
The intensity of the electric field is 30,000 N/C
Explanation:
The strength of the electric field produced by a single-point charge is given by the equation
where:
is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the magnitude of the charge
r = 3 cm = 0.03 m is the distance at which we are calculating the field intensity
Substituting, we find:

Learn more about electric field:
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The answer is 5kg m/s with the second momentum being 10 kg m/s. i took the test and it was right. hope this helps yalls