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kkurt [141]
3 years ago
12

A force of 5N compresses a spring by 4cm. Find the force constant of the spring.​

Physics
1 answer:
marissa [1.9K]3 years ago
6 0

Answer:

k = 1,250 N/m

Explanation:

Use the formula F=kx, with F=5N and x=0.04m

Then the spring constant (k) is 5/0.04

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Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly becau
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The charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Similar charges repel each other, whereas charges that are opposed attract each other.

Given data;

Electric force,F = 9 × 10 ⁻⁹ N

Distance between charges,d = 7 × 10⁻⁴ m

Chrge,q₁ = q₂ =q C

From Columb's law;

\rm F = K \frac{q_1q_2}{d^2} \\\\ 9 \times 10^{-9}  = 9 \times 10^9 \frac{q^2}{(7 \times 10^{-4})^2} \\\\ q^2 = 4.9 \times 10^{-25} \\\\  q = 7 \times 10^{-13} \ C

Hence the charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C

To learn more about Columb's law refer to the link;

brainly.com/question/1616890

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7 0
2 years ago
A wire perpendicular to the screen carries a current in the direction shown.
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A) Up is the direction of the magnetic field at point Z.

4 0
3 years ago
Read 2 more answers
Find the velocity of a wave that has a wavelength of 2 meters and a frequency of 2.1Hz
vodomira [7]
It is 4.2 hope i helped

7 0
3 years ago
A lab cart flies off the end of a track on a lab table with a horizontal velocity of 2.08 m/s. If it lands 0.96 meters from the
lana [24]

Answer:

Option C. 1.2 m

Explanation:

The following data were obtained from the question:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Height (h) of the table =?

Next, we shall determine the time taken for the lab cart to get to the ground. This can be obtained as follow:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Time (t) =?

s = ut

0.96 = 2.08 × t

Divide both side by 2.08

t = 0.96 / 2.08

t = 0.5 s

Finally, we shall determine the height of the table as illustrated below:

Time (t) = 0.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) of the table =?

h = ½gt²

h = ½× 9.8 × 0.5²

h = 4.9 × 0.25

h = 1.2 m

Thus, the height of the table is 1.2 m

3 0
3 years ago
Larry drives 20.0 km to the east from his house then 20.0 km west back to his house, takes 5.0 mins to find his wallet and leave
Scorpion4ik [409]

Larry's average speed is 
                                       (total distance) / (total time).

                      Speed = (80 km) / (60 min) = 80 km/hr .


Larry's average velocity is  
                                         (distance between start- and end- points),
                                  in the direction from the start-point to the end-point.

                       Velocity = (40 km east) / (60 min) = 40 km/hr east .

4 0
3 years ago
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