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kkurt [141]
3 years ago
12

A force of 5N compresses a spring by 4cm. Find the force constant of the spring.​

Physics
1 answer:
marissa [1.9K]3 years ago
6 0

Answer:

k = 1,250 N/m

Explanation:

Use the formula F=kx, with F=5N and x=0.04m

Then the spring constant (k) is 5/0.04

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Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
Explain what happens to the energy in a group in a system if one object loses energy according to the Law of Conservation of Ene
konstantin123 [22]

energy never disappears, for example, if you give some kinetic energy to a ball and it stops few seconds later, friction steals this energy to ground which ball was going on. "Law of Conservation of Energy" tell us that energy can't disappear

5 0
3 years ago
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Arte-miy333 [17]

Answer:

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7 0
3 years ago
The highest speed of a cheetah is 100 km/hr and the highest speed of a gazelle is 80 km/hr. If at t = 0 both animals are running
Tju [1.3M]

Answer:

t=18s

Explanation:

The final position of an object moving at constant speed is given by the formula x=x_0+vt, where x_0 is its initial position, v its speed and t the time elapsed.

For the cheetah we have x_c=x_{0c}+v_ct, and for the gazelle x_g=x_{0g}+v_gt. We want to know at which t their positions are equal, that is, x_c=x_g, which means,

x_{0c}+v_ct=x_{0g}+v_gt

Where we can do:

v_ct-v_gt=x_{0g}-x_{0c}

(v_c-v_g)t=x_{0g}-x_{0c}

t=\frac{x_{0g}-x_{0c}}{v_c-v_g}

We then substitute the values we have (the initial position of the cheetah is 0m), writing the meters in km so distance units cancel out correctly:

t=\frac{0.1km-0km}{100km/hr-80km/hr}=0.005hr=18s

On the last step we just multiply by 3600 because is the number of seconds in an hour.

3 0
4 years ago
If the air inside a balloon exerts a force of 1.5 N on an area of 0.5m^2 what is the pressure inside the ballon
Gre4nikov [31]
Pressure applied on a system is calculated by dividing the force by the area perpendicular to the direction of the force. It is expressed as:

P = F/A = 1.5 N / 0.5 m^2 = 3 N/m^2

Therefore, the correct answer from the choices is the last option. Hope this answers the question. Have a nice day.
6 0
3 years ago
Read 2 more answers
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