a 20 kg sig is pulled by a horizontal force such that the single rope holding the sign make an angle of 21 degree with the verti

Question

3 years ago

11

cle assuming the sign is motionless find the magnitude of the tension in the ropend the magnitude of the horizontal force?

1 answer:

True [87] · Answer 1 · 2022-06-02T00:02:02+03:00

True [87]3 years ago

6 0

Answer:

T= 210.15 N

F= 75.31 N

Explanation:

Let the tension in string be T newton.

According to the question

⇒T×cos21°= mg

⇒T= mg/cos21°

⇒T=20×9.81/cos21

⇒T= 210.15 N

now, the magnitude of horizontal force

F= Tsin21°

⇒F= 210.15×sin21°

=75.31 N