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3 years ago

The sum of the measures of the interior angles of a convex polygon is 360 degrees? How many sides does the polygon have?

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

Answer: the polygon has

Four sides

Step-by-step explanation:

A square has 4 interior angles of 90° each. 4×90°=360°

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Please help! Really easy math, need it asap!!! It's in the picture

Dominik [7]

Answer:

answers are: (-1,-2), (1,2), (-1,5), (1,-5). in other words, option 2, 6, 7, and 8.

Step-by-step explanation:

hope it helps

3 0

3 years ago

(N * 3) + 6 - (n * 2) = n + 3 what is value of n

GalinKa [24]

(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution

7 0

3 years ago

Read 2 more answers

Simplify the expression. State any excluded values.<br><br> x^ 2 - 36/42x - 7x^ 2

REY [17]

Consider the expression $x^2-\dfrac{36}{42}x-7x^2.$

This expression contains two terms with $x^2,$ group them:

$x^2-7x^2=x^2(1-7)=-6x^2.$

Now simplify term $\dfrac{36}{42}x=\dfrac{6}{7}x.$

Now $x^2-\dfrac{36}{42}x-7x^2=-6x^2-\dfrac{6}{7}x=6\left(-x^2-\dfrac{1}{7}x\right)=-6x\left(x-\dfrac{1}{7}\right).$

This expression is defined for all x.

3 0

3 years ago

Hop on the baby waveeeee. put your baby pic as your profile pic to make a trenddddd

Alex787 [66]

Answer:

I did it is in my profile

Step-by-step explanation:

8 0

3 years ago

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$

4 0

3 years ago