Slope = (5+7)/(1-4) = 12/-3 = -4
slope = -4
y = mx + b
-7 = -4(4) + b
-7 = -16 + b
b = 9
equation
y = -4x + 9
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-
Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
Answer:
Divide both sides by V
Step-by-step explanation:
The equation is not well written.
Mariko needs to solve the equation below for D. Here is the equation:
M = DV
For Mariko to get D, he needs to make D the subject of the formula by dividing both sides of the equation by the coefficient of D i.e V as shown;
Divide both sides by V
M/V = DV/V
V at the denominator will cancel out the V at the numerator to have:
M/V = D
Rearrange
D = M/V
Therefore, the statement which correctly describes the step he should take is:
Divide both sides by V. Option B is correct.
Answer:
30 kilometers
Step-by-step explanation:
40 min=2/3 hour
2/3*45=30
2x-3y=-14/×(-3) <=>-6x +9y=42
3x-2y=-6/×2<=>6x-4y=-12 se reduce -6x cu 6x si ne ramane 5y=30<=>y=6 , luom o ec care o vrem si inlocuim pe y cu 6 ...3x -2x=-6<=>3x-12=-6<=>3x=6<=>x= 2 , x-y=2-6=-4
