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DIA [1.3K]
3 years ago
12

Find the midpoint on segment AB; A (0, 6), B (4, 2)

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0

Answer:

2,4

Explanation:

Because a midpoint is the middle of the line

lana [24]3 years ago
5 0

Answer:

mAB=(2,4)

Step-by-step explanation:

Step 1: Use the midpoint formula to solve

mAB=(\frac{x1 +x2}{2},\frac{y1+y2}{2} )

mAB=(\frac{0+4}{2},\frac{6+2}{2} )

mAB=(\frac{4}{2},\frac{8}{2} )

mAB=(2,4)

Therefore the midpoint on the line segment AB is (2,4)

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How many bucketloads would it take to bucket out the world’s oceans? Write your answer in scientific notation.
kodGreya [7K]

Answer: 7\times10^{19} buckets

Step-by-step explanation:

Given:  A cubic kilometer=10^{15}cubic centimeters

The volume of  world’s oceans=1.4\times10^{9} cubic kilometers of water.

⇒ The volume of  world’s oceans=1.4\times10^{9}\times10^{15} cubic centimeters of water.

Volume of a bucket = 20,000 cubic centimeters of water.

The number of bucket-loads would it take to bucket out the world’s oceans

n=\frac{\text{volume of ocean}}{\text{volume of bucket}}=\frac{1.4\times10^{9}\times10^{15}}{20000}

\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}

hence,  7\times10^{19} bucketloads would it take to bucket out the world’s oceans.

5 0
3 years ago
Jason has a bar of chocolate he gives his friend 2/5 of his chocolate bar.what percentage of his bar of chocolate does he have l
ddd [48]

Answer:

60%

Step-by-step explanation:

he gave away 2/5 which is 40%. 100%-40% is 60%

8 0
3 years ago
Read 2 more answers
Oct 09, 11:40:51 AM
kumpel [21]
Get it sis 57
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8 0
3 years ago
What's the scientific notation of 0.000028
Dmitry_Shevchenko [17]
2.8 x 10^-5 good luck
7 0
3 years ago
Read 2 more answers
URGENT HELP PLEASE!
Vaselesa [24]

Answer:

(a) x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b) x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}

Step-by-step explanation:

It is given that 0\leq x\leq 2\pi.

(a)

\sqrt{2}\sin 2x=1

\sin 2x=\dfrac{1}{\sqrt{2}}

\sin 2x=\dfrac{\pi}{4}

2x=\dfrac{\pi}{4},\dfrac{3\pi}{4},\dfrac{9\pi}{4},\dfrac{11\pi}{4}     [\because \sin x=\sin y\Rightarrow x=n\pi+(-1)^ny]

x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b)

\csc^2 x-\csc x-2=0

\csc^2 x-2\csc x+\csc x-2=0

\csc x(\csc x-2)+1(\csc x-2)=0

(\csc x+1)(\csc x-2)=0

\csc x=-1\text{ or }\csc x=2

\sin x=-1\text{ or }\sin x=\dfrac{1}{2}         [\because \sin x=\dfrac{1}{\csc x}]

x=\dfrac{3\pi}{2}\text{ or }x=\dfrac{\pi}{6},\dfrac{5\pi}{6}

Therefore, x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}.

5 0
3 years ago
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