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3 years ago

What is the hypotenuse of a right triangle given the sides 7 cm and 9 cm round to the nearest 10th

Mathematics

1 answer:

AleksAgata [21]3 years ago

3 0

The hypotenuse is 11.4 cm long

Step-by-step explanation:

We have to find the hypotenuse so the other sides are:

$Perpendicular = P = 7\ cm\\Base = B = 9\ cm\\$

Pythagoras theorem will be used to find the length of Hypotenuse

$H^2=P^2+B^2\\$

Putting values

$H^2=(7)^2+(9)^2\\H^2=49+81\\H^2=130$

Taking square Root on Both sides

$\sqrt{H^2}=\sqrt{130}\\H=11.40$

Rounding off to the nearest tenth

$H=11.4\ cm$

Hence,

The hypotenuse is 11.4 cm long

Keywords: Triangle, Pythagoras Theorem

Learn more about Pythagoras theorem at:

#LearnwithBrainly

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