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goblinko [34]
3 years ago
12

(5, 3) and (6, r) m = -1

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

r = 2

Step-by-step explanation:

(2-3)/(6-5)

= -1/1

= -1

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The temperature, in degrees fahrenheit (°
vova2212 [387]
The temperature decreased by 5 degrees per hour, as -25 / 5 is -5.
5 0
3 years ago
Which system is equivalent to
sammy [17]

<u>Answer:</u>

D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11

<u>Step-by-step explanation:</u>

We are given the following two expressions:

3x^2-4y^2=25

and

-6x^2-2y^2=11

Now if we look at the option D) 6x^2 - 8y^2 = 50&#10; and -6x^2 - 2y^2 = 11, we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25

and the later part -6x^2 - 2y^2 = 11 is already the same.

Therefore, the correct answer option is D)  6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

6 0
3 years ago
Read 2 more answers
Find the value of x in the triangle shown below.
kobusy [5.1K]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Mai's mother was 28 when Mai was born. Mai is now 12 years old. In how many years will Mai's mother be twice Mai's Age
noname [10]

Answer:

4

Step-by-step explanation:

Let x = the number of years

In x years, Mai's mother's age will be: 28 + x

                         and Mai's age will be:  12 + x

Then,                                      28 + x = 2(12 +   x)

Distribute the 2                      28 + x =    24 + 2x

Subtract 24 from each side     4 + x =            2x

Subtract x from each side             x = 4

In four years, Mai's mother will be twice Mai's age.

<em>Check: </em>

28 + 4 = 2(12 + 4)

   32   = 2 ×  16

   32   =   32

6 0
3 years ago
Solve 2x^2 + x - 4 = 0 <br> X2 +
damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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