The number of hours a group of 12 children in Mrs. Smith's kindergarten class read in a day.

Find the value of X to the nearest tenth:

castortr0y [4]

Answer:

13.0

Step-by-step explanation:

sin(65°) × 14.3 would give u 12.9 then u round it to the 13

5 0

3 years ago

The graph of the function C(x) = −0.34x2 + 12x + 62 is shown. The function models the production cost, C, in thousands of dollar

Virty [35]

Answer:

0 ≤ x < 1.12 and 34.18 < x ≤ 39.87

Step-by-step explanation:

Let

x ----> is the number of tires produced, in thousands

C(x) ---> the production cost, in thousands of dollars

we have

$C(x)=-0.34x^{2} +12x+62$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The graph in the attached figure

we know that

Looking at the graph

For the interval [0,1.12) -----> $0\leq x$

The value of C(x) ----> $C(x) < 75$

That means ----> The production cost is under $75,000

For the interval (34.18,39.87] -----> $34.18 < x\leq 39.87$

The value of C(x) ----> $C(x) < 75$

That means ----> The production cost is under $75,000

Remember that the variable x (number of tires) cannot be a negative number

therefore

If the company wants to keep its production costs under $75,000 a reasonable domain for the constraint x is

0 ≤ x < 1.12 and 34.18 < x ≤ 39.87

7 0

3 years ago

Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

<em>Choose the first alternative</em>

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

3 years ago

Read 2 more answers

One bricklayer can build a wall in 6 hours. Another bricklayer could build the same wall in 4 hours. If they work together, how

Natasha2012 [34]

Answer:

they work together, it will take 2.4 hours to build the wall.

Step-by-step explanation:

One bricklayer can build a wall in 6 hours.

One hour work = $\frac{1}{6}$

Another bricklayer can build the same wall in 4 hours.

One hour work = $\frac{1}{4}$

They can together, how long will take them to build the wall.

Let's take "t" the time taken to build the wall.

The sum of their work rate = 1 (To build the wall)

$\frac{t}{6} + \frac{t}{4} = 1$

Now we have to solve this equation. Take LCD of 6 and 4.

The LCD (least common divisor) of 6 and 4 is 12.

$\frac{2t + 3t}{12} = 1$

5t = 12*1

5t = 12

Dividing both sides by 5, we get

t = $\frac{12}{5}$

t = 2.4 hours.

So, they work together, it will take 2.4 hours to build the wall.

6 0

3 years ago

And object has a mass of five KG what force is needed to accelerate it at 6m/s2

ivann1987 [24]

Answer:30N

Step-by-step explanation:

Mass=5kg

Acceleration=6m/s^2

Force =mass x acceleration

Force =5 x 6

Force=30N

4 0

3 years ago