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3 years ago

12

Travis planned to watch 4 dogs while his neighbors were out of town for a week. Each dog would need to eat 612 ounces of dog foo

d. How many ounces of dog food were needed for all the dogs?

2 answers:

Finger [1]3 years ago

8 0

I believe it would be 2448 ounces. 4 X 612= 2448

Zarrin [17]3 years ago

4 0

If each dog needs 612 oz and there are 4 dogs then 612 multiplied by 4 is 2448

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Xsquared+11x+28+xsquared+13x+40

UNO [17]

X² + 11x + 28 + x² + 13x + 40

combine like terms

x² + x² = 2x²
11x + 13x = 24x
28 + 40 = 68

2x² + 24x + 68 is your answer

if you want it simplified:

2(x² + 12x + 34)

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A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia

iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
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\\\\\\
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what's the population in 2004? well, from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004

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