Ask question

Ask question

All categories

3 years ago

12

Travis planned to watch 4 dogs while his neighbors were out of town for a week. Each dog would need to eat 612 ounces of dog foo

d. How many ounces of dog food were needed for all the dogs?

2 answers:

Finger [1]3 years ago

8 0

I believe it would be 2448 ounces. 4 X 612= 2448

Zarrin [17]3 years ago

4 0

If each dog needs 612 oz and there are 4 dogs then 612 multiplied by 4 is 2448

You might be interested in

What is the value of x?

grandymaker [24]

i got 5.14cm i don´t know how much you are supposed to round though

36/42= 0.857142857 x 6=5.142857143

6 0

2 years ago

Shawna bought a bag of candy. She ate of the bag on Friday and of the bag on Saturday. What portion of the bag is left?

vodka [1.7K]

Answer:

I believe it would be A hope this helps!

Step-by-step explanation:

5 0

2 years ago

viet learned 25 new spelling words last week. He learned 5 times as many words as Max. How many words did Max learn? Draw a lbar

masya89 [10]

Max learned 125 new spelling words i know this becuse 25 times 5 is 125

8 0

2 years ago

dlinn [17]

Answer:72.1

103*.7=72.1

I hope this is good enough:

6 0

2 years ago

Find the 75th term of the arithmetic sequence -17, -13, -9....

Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

Step-by-step explanation:

Given the sequence

$-17, -13, -9....$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4$

The difference between all the adjacent terms is the same and equal to

$d=4$

The first element of the sequence is:

$a_1=-17$

now substitute $d=4$ and $a_1=-17$ in the nth term of the sequence

$a_n=a_1+\left(n-1\right)d$

$a_n=4\left(n-1\right)-17$

$a_n=4n-21$

Now, substitute n = 75 in the $a_n=4n-21$ sequence to determine the 75th sequence

$a_n=4n-21$

$a_{75}=4\left(75\right)-21$

$a_{75}=300-21$

$a_{75}=279$

Therefore, the 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

3 0

3 years ago