1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve
Here is an example:
4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side. It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.
<span>Hope that helps</span>
Answer:
19
Step-by-step explanation:
First: Recognize that (f o g)(x) is the "composition" of two functions, where g(x) serves as the input to f(x). We are given f(x) = 2x+3 and g(x) = x+5. You could find g(3) right now: it is g(3) = 3+5 = 8. Use this 8 as the input to f(x): f(8) = 2(8)+3 = 19.
Answer:
10 cuadrados
Step-by-step explanation:
Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.
28 - 8 = 20cm
20cm / 2cm = 10cm
Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo
10cm * 4cm = 40
el cuadrado de 2cm tendra un area de
2cm * 2cm = 4
Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo
40 / 4 = 10 cuadrados
A triangles has side lengths of 7, 10 and 11 what is the perimeter of the triangle formed by joining the midpoints of these sides?
The Answer is
X=10
Explanation:
