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valina [46]
4 years ago
7

An object has a mas of 5 kg what force is needed to accelerate it at 6

Mathematics
1 answer:
stiv31 [10]4 years ago
6 0

Force (F) = mass (m) * acceleration (a)

F = (5 kg) * (6 m/s²)

  = 30 newtons

Answer: 30 N

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What value of x is in the solution set of 2(4+2x)>5x+5
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Answer:

x < 3

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2(4+2x)>5x+5

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8 +4x > 5x+5

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8 +4x-4x > 5x-4x+5

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If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?
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Answer:

Value of \sec \theta = \frac{5}{4}

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of \sec \theta.

By definition of secants;

\sec \theta = \frac{1}{\cos \theta}

Now, first find the cosine of angle \theta

As the point (12 , -9) lies in the IV quadrant , where \cos \theta > 0

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225

or

Hypotenuse = \sqrt{225} =15 units

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

\cos \theta = \frac{Adjacent side}{Hypotenuse side}

then;

\cos \theta = \frac{12}{15} = \frac{4}{5}

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therefore, the value of \sec \theta is, \frac{5}{4}

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