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padilas [110]
3 years ago
8

Can any one help me

Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0
I think you set up the equation like this

$2.50x+5

I hope I helped sorry if I didn't.

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Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L​
svetlana [45]

Answer:

B

Step-by-step explanation:

P=2L+2W

P-2L=2W (Subtract 2L from both sides of the equation)

2W=P-2L (Symmetric Property of Equality)

W=\frac{P-2L}{2} (Divide both sides of the equation by 2)

W=\frac{P}{2} -\frac{2L}{2} ("Split" the fractions)

W=\frac{1}{2}P-L (Simplify)

Hope this helps!

4 0
2 years ago
Can someone plz help me with this
Ronch [10]
The line is right in the middle of 100 and 110 degrees so the answer should be 105 degrees. This tool is called a protractor. :)
3 0
3 years ago
Read 2 more answers
Will give brainlesr please help im 25% blind
My name is Ann [436]

Answer:

Option D

Step-by-step explanation:

the height of the first rectangle ( 30 ) over the height of the other rectangle     ( 3 )  is 30/3 and equals 10

the length of the first rectangle ( 60 ) over the length of the second rectangle  ( 6 )  is 60/6 and equals 10

the ratio of the sides of both rectangles are equivalent therefore the are similar

3 0
3 years ago
Write the point-slope form of the equation for a line that passes through (6, -1) with a slope of 2.
Naddika [18.5K]

Answer:

2x-y-13=0

Step-by-step explanation:

6 0
3 years ago
To help consumers assess the risks they are​ taking, the Food and Drug Administration​ (FDA) publishes the amount of nicotine fo
Anni [7]

Answer:

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 9 - 1 = 8

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.8595

The margin of error is:

M = T*s = 1.8595*2.7 = 5

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams

The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

7 0
3 years ago
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