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3 years ago

original price of a calendar: $14.50 discount: 30% find the new price for the item after the discount

2 answers:

5 0

Here, Original price = $14.50
Discount = 30%

Now, Amount of discount = 14.50*0.30 = $4.35

So, price after discount would be: $14.50 - $4.35 = $10.15

Your answer is $10.15

Hope this helps!

sergeinik [125]3 years ago

4 0

First find 30% of $14.50

= 30/100 x 14.50
=$4.35

Than take away $4.35 away from $14.50
=14.50 - 4.35
=$10.15

Therefore the new price is $10.15

:)

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3 years ago

A right triangle has leg measures of 8 and 15 inches. What is the area and perimeter of the triangle?

rewona [7]

Hello!

<h3><em><u>Answer</u></em></h3>

The area of the right triangle is 30 $in^{2}$ . The perimeter is 40 in.

<h3><em><u>Explanation</u></em></h3>

First, we must find the measure of the hypotenuse of the triangle by using the Pythagorean Theorem.

$a^{2}$ + $b^{2} = c^{2}$

$8^{2} + 15^{2} = c^{2}$

64 + 225 = $c^{2}$

√289 = $c^{2}$

17 = $c$

Now that we have all the side lengths, we can use the formulas to find the area and perimeter.

A = $\frac{bh}{2}$

A = (15 × 8) ÷ 2

A = 30

<h3>PERIMETER:</h3>

P = a + b + c

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3 years ago

The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func

alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

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Solution:

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$Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq 0\\-112 \geq 0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq 0\\80 \geq 0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq 0\\-112 \geq 0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution$