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Tema [17]
4 years ago
13

What is the smallest part of an element?

Chemistry
2 answers:
max2010maxim [7]4 years ago
7 0
An B: Atom is the smallest part of an element


hope this helps
Umnica [9.8K]4 years ago
6 0
The smallest particle of an element that can exist is called an Atom.

I really hope this helps you and have a great day!! :)
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The pictures showed an organ system in the human body
LenaWriter [7]
The answer is D okay
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3 years ago
In an endothermic reaction, the ______ have more energy than the _______.
choli [55]

Answer:

C

Explanation:

If the products have a higher energy level than the reactants then the reaction is endothermic.

In an endothermic reaction, the reaction mixture absorbs heat from the surroundings. Therefore, the products will have a higher energy than the reactants and ΔH will be positive.

In an exothermic reaction, the reaction mixture releases heat to the surroundings. Therefore, the products will have a lower energy than the reactants and ΔH will be negative.

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When carbon dioxide is formed, one carbon atom forms double covalent bonds with two oxygen atoms. Carbon dioxide is considered
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The carbon is considered because it is form by oxygen atoms
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3 years ago
Los catalizadores sirven para detener una reacción química ?
Contact [7]

Answer:

si

Explanation:

Los catalizadores son sustancias que aceleran una reacción química, proporcionando una ruta alternativa para romper y formar nuevos enlaces entre átomos. Su importancia reside en el hecho de que este nuevo camino requiere menos energía que el original, lo que facilita el proceso.

5 0
3 years ago
300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You
Bas_tet [7]

Explanation:

It is given that volume of Pb(NO_{3})_{2} is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

            PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)

K_{sp} for PbCl_{2} is given as 1.7 \times 10^{-5}.

As, molarity is number of moles present in liter of solution.

Hence, moles of Pb^{2+}(aq) will be calculated as follows.

         moles of Pb^{2+}(aq) = 0.300 L \times 0.200 M

                                                = 0.06 mol

                      [Pb^{2+}] = \frac{0.06 mol}{0.5 L}

                                            = 0.120 M

Mole of Cl^{-}(aq) = 0.2 L \times 0.05 M  

                                  = 0.010 M

Now,   Q = [Pb^{2+}][Cl^{-}]^{2}

                  = 0.120 \times (0.010)^{2}

                  = 1.2 \times 10^{-5}    

As, Q < K_{sp} hence, there will be no formation of PbCl_{2} precipitate.

3 0
3 years ago
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