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Len [333]
3 years ago
10

02.01]In the 1800s, John Dalton's atomic theory was that atoms are indivisible. Later, subatomic particles such as neutrons, ele

ctrons, and protons were discovered. What happened to the indivisible part of Dalton's atomic theory, and why? The theory remained unchanged because Dalton was correct regarding all other statements within the accepted scientific theory. Dalton's theory remained intact, and the new evidence was ultimately discarded because new data must fit within the current accepted theory. The indivisible part of the theory was voted upon by the scientific community because validity is based on the majority of scientific opinions. The indivisible part of the theory was discarded after the subatomic particles discovery because consensus of data must exist for theories to be valid.
Chemistry
2 answers:
Luda [366]3 years ago
8 0
The last one is the correct answer. The atomic structure can be broken down which is what the findings concerning protons, electrons and neutrons showed. The theory was thus modified. What remained was no chemical reaction could affect the basic structure of an atom.

Still the last choice is still true. The first choice is your second best answer because of what I wrote in the last sentence of the above paragraph. 

Last Choice <<<<< answer
nydimaria [60]3 years ago
7 0

Answer:

The correct answer will be option- The indivisible part of the theory was discarded after the subatomic particles discovery because consensus of data must exist for theories to be valid.

Explanation:

John Dalton is known for his atomic theory which states that matter is made up of indivisible atoms.  

The subatomic particles of the atom were first discovered by J.J Thomson in 1897 when he discovered electrons, In 1920 Rutherford discovered protons and in 1932 James Chadwick discovered neutrons.

This led to a shift in the paradigm that atom is indestructible as new discoveries led to changes in the consensus data which opposed the atomic theory. This discarded the indivisible atomic theory.

Thus, the selected option is the correct answer.

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Luba_88 [7]

Answer:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

Explanation:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

6 0
2 years ago
PLZZZZZ HELPPP THANK U 10 ptsssss
balandron [24]
Hi!

I think the oxidation state of all the atoms should change. :)

Hope this helps
6 0
3 years ago
Iron and oxygen react together to make iron (III) oxide (rust). You know that this is a chemical reaction and not a nuclear reac
Alona [7]
The atoms didn't change we only added 2 different ones together. 2nd one is right
7 0
3 years ago
Read 2 more answers
What is the mass of the solid NH4Cl formed when 75.5 g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas
Gekata [30.6K]

Answer : The volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of NH_4Cl produced is, 110.7 grams.

Explanation :

The balanced chemical reaction will be:

NH_3+HCl\rightarrow NH_4Cl

First we have to calculate the moles of NH_3 and HCl

\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}

Molar mass of NH_3 = 17 g/mole

\text{Moles of }NH_3=\frac{75.5g}{17g/mole}=4.44mole

and,

\text{Moles of }HCl=\frac{\text{Mass of }HCl}{\text{Molar mass of }HCl}

Molar mass of HCl = 36.5 g/mole

\text{Moles of }HCl=\frac{75.5g}{36.5g/mole}=2.07mole

Now we have to calculate the limiting and excess reagent.

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NH_3

So, 2.07 mole of HCl react with 2.07 mole of NH_3

From this we conclude that, NH_3 is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles

Now we have to calculate the volume of the gas remaining.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of gas = 752 mmHg = 0.989 atm     (1 atm = 760 mmHg)

V = Volume of gas = ?

n = number of moles of gas = 2.37 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 14.0^oC=273+14.0=287K

Putting values in above equation, we get:

0.989atm\times V=2.37mole\times (0.0821L.atm/mol.K)\times 287K

V = 56.5 L

Now we have to calculate the moles of NH_4Cl

As, 1 mole of HCl react with 1 mole of NH_4Cl

So, 2.07 mole of HCl react with 2.07 mole of NH_4Cl

Now we have to calculate the mass of NH_4Cl

\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl

Molar mass of NH_4Cl = 53.5 g/mole

\text{ Mass of }NH_4Cl=(2.07moles)\times (53.5g/mole)=110.7g

Thus, the volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of NH_4Cl produced is, 110.7 grams.

3 0
3 years ago
In response to action potentials arriving along the transverse tubules, the sarcoplasmic reticulum releasesA) acetylcholine.B) s
stealth61 [152]

Answer:

Calcium ions.

Explanation:

The generation of the action potential helps in the transfer of information to the different body parts. This potential occurs to the difference in membrane potential inside and outside of the cell.

The sarcoplasmic reticulum is the homologous to the endoplasmic reticulum of the cells. The sarcoplasmic reticulum contains calcium ions in it and releases the stored calcium ions on the generation of the action potential. This calcium ion is important for the action of the actin and myosin.

Thus, the correct answer is option (D).

7 0
3 years ago
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