The statements that describe a nuclear reaction are may involve a change in total mass, involve very high-energy changes, and involve changes in nuclides when decay takes place.
There are two kinds of nuclear reactions, that is, fission and fusion. Fusion involves the fusion of two light atoms into a heavier atom, while fission involves the splitting of an unstable isotope (with a high mass number) into stable elements of lower mass number, which vary in features from the parent atoms. Both the reactions discharge huge concentration of energies in the process.
Answer : The amount of heat released is, -121.04 KJ
Solution : Given,
Enthalpy of reaction, 
= -890 KJ
Mass of methane = 6 g
Molar mass of methane = 44 g/mole
First we have to calculate the moles of methane.
The given balanced reaction is,
From the balanced reaction we conclude that
1 mole of methane releases heat = -890 KJ
0.136 moles of methane releases heat = 
Therefore, the amount of heat released is, -121.04 KJ
Has Mas and takes up Space
use variable
1K₂MnF₆ + aSbF₅⇒ bKSbF₆ + cMnF₃ + dF₂
K, left=2,right=b⇒b=2
Mn, left=1, right=c⇒c=1
Sb, left=a, right=b⇒a=b=2
F, left=6.1+5a, right=6b+3c+2d
equation:
6+5(2) = 6(2)+3(1)+2d
16=15+2d
1=2d
d=0.5
So the reaction equation becomes:
1K₂MnF₆ + 2SbF₅⇒ 2KSbF₆ + 1MnF₃ + 0.5F₂ x2
2K₂MnF₆ + 4SbF₅⇒ 4KSbF₆ + 2MnF₃ + F₂
Answer:
12.9 g O₂
Explanation:
To find the mass of oxygen gas produced, you need to (1) convert grams KClO₃ to moles KClO₃ (via molar mass from periodic table values), then (2) convert moles KClO₃ to moles O₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles O₂ to grams O₂ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to match the given value (33.0 g).
Molar Mass (KClO₃): 39.098 g/mol + 35.45 g/mol + 3(15.998 g/mol)
Molar Mass (KClO₃): 122.542 g/mol
2 KClO₃ ---> 2 KCl + 3 O₂
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
33.0 g KClO₃ 1 mole 3 moles O₂ 31.996 g
-------------------- x ------------------- x ----------------------- x ------------------ =
122.542 g 2 moles KClO₃ 1 mole
= 12.9 g O₂
