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Llana [10]
3 years ago
6

I need help on these questions

Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0
A. 24in/min
b. 24x/min
c. 2
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Find the length of side AB
telo118 [61]

Answer:

AB ≈ 5.6 cm

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos62° = \frac{adjacent}{hypotenuse} = \frac{AB}{BC} = \frac{AB}{12} ( multiply both sides by 12 )

12 × cos62° = AB , thus

AB ≈ 5.6 cm ( to 1 dec. place )

6 0
3 years ago
The exterior angles of triangle UVW are ∠X, ∠Y, and ∠Z, and they are adjacent to ∠U, ∠V, and ∠W, respectively.
LiRa [457]

Answer:

the answer is 97, I'll explain in the comments in a bit

6 0
3 years ago
Simplify the expression. (5x^3+4x^2+6x-3)+(-2x^3+3x^2-7x+9)-(5x+3)(4x^2+x-1)
kvv77 [185]

Answer:

-17x³-10x²+x+9

Step-by-step explanation:

(5x³+4x²+6x-3)+(-2x³+3x²-7x+9)-(5x+3)(4x²+x-1)

(5x³+4x²+6x-3)+(-2x³+3x²-7x+9)-(20x³+5x²-5x+12x²+3x-3)

(3x³+7x²-x+6)-(20x³+17x²-2x-3)

-17x³-10x²+x+9

5 0
3 years ago
How many times could 6 go into 49
igomit [66]

Answer:

approximately 8.16 times

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Help please math thank you
bija089 [108]

Answer:

5

Step-by-step explanation:

4 0
3 years ago
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