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gtnhenbr [62]
3 years ago
15

How to solve this equation 6x^2-2x+5+2x^2-7x-11

Mathematics
1 answer:
postnew [5]3 years ago
6 0

x= \frac{9+\sqrt{273} }{16}

OR

x= \frac{9-\sqrt{273} }{16}

Step-by-step explanation:

The given equation is

6x^{2}-2x+5+2x^{2}-7x-11

<u>Step 1: Arrange the equation</u>

6x^{2}+2x^{2}-2x-7x-11+5

<u>Step 2: Simplify the equation</u>

8x^{2}-9x-6

<u>Step 3: Identify a,b,c in the equation</u>

a=8

b=-9

c=-6

<u>Step 4: Apply quadratic formula to find the possible values of x</u>

x = \frac{-b±\sqrt{b^{2}-4ac } }{2a}

x= \frac{-(-9)±\sqrt{(-9)^{2}-4(8)(-6) } }{2(8)}

x= \frac{9+\sqrt{273} }{16}

OR

x= \frac{9-\sqrt{273} }{16}

Keyword: Equation

Learn more about equations at

  • brainly.com/question/4460262
  • brainly.com/question/8955867

#LearnwithBrainly

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