There is a theorem that says if parallel lines are cut by a transversal, then same-side interior angles are supplementary (add up to 180 degrees).
If lines p and r were parallel, then angles 28 and (3x + 2) would add up to 180 degrees.
(28) + (3x + 2) = 180
3x + 30 = 180
3x = 150
x = 50
Answer:
The measure of angle ADE is equal to 62 degrees.
Step-by-step explanation:
Firstly, I want to remind you that the sum of the interior angles in a quadrilateral are 360 degrees. Now, we are given that CD || BA and CB || DA, which means that this quadrilateral is a parallelogram. This is important because we know that the opposite angles in a parallelogram are congruent, which means that angle C is congruent to angle A and angle B is congruent to angle D. Therefore, the measure of angle A is also 73 degrees. Next, we can represent angle D as x, which means that angle B is equal to x, so the sum of angle D and B is 2x. Finally, we can set up an equation where we solve for the value of x, and then subtract it with 45 degrees:
2x + 2(73) = 360
2x + 146 = 360
2x = 214
x = 107 = B = D
Now, we can subtract the measure of angle D with 45 degrees to get the measure of angle ADE:
ADE = 107 - 45
ADE = 62
You should use 12$ per because your overall profit was higher. Lower cost means less profit but higher number of buyers
Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
Answer:
2 real solutions
Step-by-step explanation:
Remember this messy thing?
The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.
For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.
