Answer:
3. 3(x+y)(x-y)
4. (y²+4)(y+2)(y-2)
5. 2(3x+1)(x+2)
Step-by-Step:
3. 3(x²-y²) = 3(x+y)(x-y)
4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)
5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)
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Its 16.
So you have 12 miles on that trail, and markers every 2/3 of the way there. If you were to divide 2 with 3 then you can get the decimal of the fraction. Which in this case it’s 0.75. So every single 0.75 of the mile there is a marker. Divide 12 with 0.75 and you get 16 markers.
Hoped this helped in some way.
Answer:
Step-by-step explanation:
i would love to help but you need to include either the measurement or a screen shot/picture of the equation.
Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.