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Semmy [17]
3 years ago
9

Find the indicated root

Mathematics
2 answers:
Tanzania [10]3 years ago
8 0

Answer:

{n}^{25}

Step-by-step explanation:

\sqrt[3]{ {n}^{75} }  \\  {n}^{ \frac{75}{3} }  \\  =  {n}^{25}

hope this helps

brainliest appreciated

good luck! have a nice day!

Sever21 [200]3 years ago
6 0

So you have to put 25 inside the blank box.

look at the attached picture

Hope it will help you

Good luck on your assignment

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Which is the best estimate of 59.4 × 0.28
Kobotan [32]

Answer:      17.7.  

59.4 * 0.28 = 59 * 0.3

Step-by-step explanation:  ---------->

59 * 0.3 = ?

59 * 0.3 = 17.7

Your answer is 17.7.

I hope this helps!

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Answer:

I believe the last one is proportional

Step-by-step explanation:

simplify r/s and you will get your answer 5

I hope this helps :)


4 0
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The equation of line r is y = -12 1 2 x - 4. If line s runs perpendicular to line r and passes through (4, -3), what would be th
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I need help please ❤️❤️❤️❤️❤️
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Step-by-step explanation:

6 0
3 years ago
Assume that when adults with smartphones are randomly​ selected, 51​% use them in meetings or classes. If 11 adult smartphone us
Luba_88 [7]

Answer:

The probability is 0.2356.

Step-by-step explanation:

Let X is the event of using the smartphone in meetings or classes,

Given,

The probability of using the smartphone in meetings or classes, p = 51 % = 0.51,

So, the probability of not using smartphone in meetings or classes, q = 1 - p = 1 - 0.51 = 0.49,

Thus, the probability that fewer than 5 of them use their smartphones in meetings or classes.

P(X<5) = P(X=0) + P(X=1) + P(X=2) + P(X=3)+P(X=4)

Since, binomial distribution formula is,

P(x) = ^nC_r p^x q^{n-x}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

Here, n = 11,

Hence,  the probability that fewer than 5 of them use their smartphones in meetings or classes

=^{11}C_0 (0.5)^0 0.49^{11}+^{11}C_1 (0.5)^1 0.49^{10}+^{11}C_2 (0.5)^2 0.49^{9}+^{11}C_3 (0.5)^3 0.49^{8}+^{11}C_4 (0.5)^4 0.49^{7}

=(0.5)^0 0.49^{11}+11(0.5)0.49^{10} + 55(0.5)^2 0.49^{9}+165 (0.5)^3 0.49^{8} +330(0.5)^4 0.49^{7}

=0.235596671797

\approx 0.2356

4 0
4 years ago
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