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Gelneren [198K]
2 years ago
14

Prove that cos3A=sin2A​

Mathematics
2 answers:
melamori03 [73]2 years ago
4 0

Answer:

Step-by-step explanation:

Cos3A= Sin2A ........ (i)\\\\Cos3A= Cos (90-2A)\\\\3A= 90-2A\\\\5A= 90\\\\A= 18\\\\

<em>Now,</em>

<em>Putting the value of A to find the value,</em>

<em />From (i)\\Cos(3x18) = Sin (2x18)\\Cos54= Sin36\\0.5877= 0.5877 \\LHS=RHSProved .

Gekata [30.6K]2 years ago
4 0

Answer:

Cos3A= Sin2A ........ (i)

Cos3A= Cos (90-2A)

3A= 90-2A

5A= 90

A= 18

from (i)

Cos(3×18) = Sin (2×18)

Cos54= Sin36

0.5877= 0.5877 proved .

Step-by-step explanation:

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3 years ago
19+7 divided by 2 - 5 with brackets to equal 8?
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Answer:

8

Step-by-step explanation:

Given that

19 + 7 divided by 2 - 5

So if we solve this we have to apply proper brackets

= (19 + 7) ÷ 2 - 5

= 26 ÷ 2 - 5

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7 0
3 years ago
When two people each measured a windows width, their results were 79 cm and 786 mm. Are these results equally precise? Explain.
rosijanka [135]

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4 0
3 years ago
Solve for L: d=LM/R2+R1
Bogdan [553]
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7 0
3 years ago
Read 2 more answers
Plez help I need this for homework now
katrin2010 [14]
Firstly, put Derek and Paul's collection together:
1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910, 1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

1950+1952+1908+1902+1955+1954+ 1901+1910+1929+1935+1928+1930+ 1925+ 1932+1933+1920
=30864
=30864÷16
=1929
∴the mean is 1929.

Median:
1901, 1902, 1908, 1910, 1920, 1925, 1928, 1929, 1930, 1932, 1933, 1935,
1950, 1952, 1954, 1955
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=1.0005184
= Median

Range:
1955-1901
=54
∴the range is 54.





7 0
3 years ago
Read 2 more answers
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