What is the inverse of the linear function h(x)=x+7/4

Mathematics

1 answer:

Tresset [83]3 years ago

8 0

h(x) = x + 7/4

Replace h(x) with y

y = x + 7/4

Swap x and y

x = y + 7/4

Solve for y.

Subtract 7/4 from both sides.

y = x - 7/4

Replace y with h(x)^-1

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How do I solve this equation

Anestetic [448]

-x - y = 8
2x - y = -1

Ok, we are going to solve this in 2 parts. First we have to solve for one of the variables in one of the equation in terms of the other variable. I like to take the easiest equation first and try to avoid fractions, so let's use the first equation and solve for x.

-x - y = 8 add y to each side
-x = 8 + y divide by -1
x = -8 - y

So now we have a value for x in terms of y that we can use to substitute into the other equation. In the other equation we are going to put -8 - y in place of the x.

2x - y = -1
2(-8 - y) - y = -1 multiply the 2 through the parentheses
-16 - 2y - y = -1 combine like terms
-16 - 3y = -1 add 16 to both sides
-3y = 15 divide each side by -3
y = -5

Now we have a value for y. We need to plug it into either of the original equations then solve for x. I usually choose the most simple equation.

-x - y = 8
-x - (-5) = 8 multiply -1 through the parentheses
-x + 5 = 8 subtract 5 from each side
-x = 3 divide each side by -1
x = -3

So our solution set is

(-3, -5)

That is the point on the grid where the 2 equations are equal, so that is the place where they intersect.

4 0

3 years ago

If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco

lina2011 [118]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}$

$\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt$

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4 years ago

Pls help me, and do not send links. Thanks

ipn [44]

i uploaded a vid on this here

https://www.you tube.com/watch?v=dQw4w9WgXcQ

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3 years ago

C is the midpoint of AE. B is the midpoint of Ac. D is the midpoint of CE

emmasim [6.3K]

Answer: d is correct

Step-by-step explanation: