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Lilit [14]
3 years ago
11

The atoms in ionic compounds _______. A. Transfer electrons B. Transfer neutrons C. Share neutrons D. Share electrons

Chemistry
1 answer:
erastovalidia [21]3 years ago
4 0

A. transfer electrons

Ionic bonding is the complete transfer of valence electron(s) between atoms.

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Which of the following examples shows an increase of energy in the particles of matter? (Select THREE that are true)
aleksley [76]
Gas to liquid solids are going to break the liquid
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Explain what environmental bias means. What are the categories that
rewona [7]

Answer: Environmental bias can be defined as the idea that suggests a group of people being living in the environment which is harmful for them.

Explanation:

There are three categories that make up the environmental bias there are socio-cultural choice, occupational choice, and personal choice.

The environmental bias can be related to chemistry as chemical lab is an area prone to chemical (acid, alkali) and fire so produced in reactions thus prone to accidental hazards not safe for working of people. But people like to work in chemical lab due to their personal and occupational choice.

5 0
3 years ago
Which atomic models does Rutherford’s experimental evidence support? Explain why these models (Dalton, Bohr, Thomson models) are
ipn [44]

Answer:

Rutherford was the first scientist who proposed the nuclear model of the atom. According to his atomic model, most of the space of an atom is empty, while the nucleus containing protons and neutrons lie at the center of the atom while electrons revolve around nucleus in definite orbits.

If we talk about studies of some other scientists like Dalton, Neil Bohr and JJ Thomson, they all are compatible with Rutherford's results to a large extent.

For example: Dalton's atomic model assumed that atoms of any substance are similar in size and atoms react to form compounds. Rutherford's concept indicated that atoms contain electrons and they are in a specific number which can be shared to form compounds.

If we talk about Bohr's model, it states that electrons revolve around nucleus in specific shells, this again is compatible with Rutherford's results which gave the concept of shells.

If we talk about Thomson's Plum pudding model, that describe atom as negative particles floating within a soup of diffuse positive charge. This is also compatible with the results of Rutherford that state that negative electrons surround positive nucleus.

Rutherford's model was best atomic model but still it took help from many previous studies and therefore was compatible with the results of old models.


Hope it help!

5 0
3 years ago
Read 2 more answers
An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of
Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C

3 0
3 years ago
1 How many moles of solute are in:
Sonbull [250]

Moles of solute for both a and b are the same = 1 mol

<h3>Further explanation</h3>

Given

a 500 cm³ of solution, of concentration 2 mol/dm³

b 2 litres of solution, of concentration 0.5 mol/dm³

Required

moles of solute

Solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

Can be formulated :

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

a.

V = 500 cm³ = 0.5 L

M = 2 mol/L

n=moles = M x V

n = 2 mol/L x 0.5 L

n = 1 mol

b.  

V = 2 L

M = 0.5 mol/L

n=moles = M x V

n = 0.5 mol/L x 2 L

n = 1 mol

5 0
3 years ago
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