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AURORKA [14]
2 years ago
10

How was Earth’s atmosphere changed during the Great Oxygenation Event?

Chemistry
2 answers:
SpyIntel [72]2 years ago
8 0

Consequences of oxygenation. Eventually, oxygen started to accumulate in the atmosphere, with two major consequences. Oxygen likely oxidized atmospheric methane (a strong greenhouse gas) to carbon dioxide (a weaker one) and water.

faust18 [17]2 years ago
3 0

Answer: .Early organisms created oxygen from other gases in the atmosphere

Explanation:

It is believed that the atmosphere emerged about 4,500 million years ago, by a process that can be explained in five stages.

In the first stage, the atmosphere was shaped by volcanic emanations, such as water vapor, carbon and sulfur dioxide, and nitrogen. At this point, oxygen was barely present.

In the second stage, as the Earth cooled, the water vapor condensed and formed the oceans. Carbon dioxide reacted with the rocks of the earth's crust to create carbonates - (CO32-); a portion of them, when dissolved in the seas, generated salt water.

In the third stage, approximately 3.500 million years ago, bacteria appear, capable of carrying out photosynthesis, that is, of producing oxygen. This facilitated the development of marine life.

Once the atmosphere obtained sufficient oxygen, the fourth stage appeared, the evolution of large organisms as animals capable of breathing air.

This is how the current atmosphere containing the gases created in each of the previous phases was reached. These are kept in motion by winds and rains, allowing humans, and other living organisms, to breathe. For this reason, without them there would be no life on the planet.

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Assume that a firm has the following marginal benefit of pollution (denoted E for emissions, measured in tons): MB=150-5 E e. No
jeka57 [31]

Answer:

Explanation:

E)cost of pollution is reduction in benefit of the firms.

MB=150-5E,. MB=90-3E

E=30-MB/5. E=30-MB/3

Joint MB,

E=60-8MB/15

MB=112.5-1.875E

Total pollution reduction=24

Total pollution=60-24=36

MB=112.5-1.875*36=112.5-67.5=45

Firm 1

MB=150-5E.

45=150-5E.

E=-105/-5=21

Reduction=30-21=9

Firm 2,

MB=90-3E

45=90-3E

E=-45/-3=15

Reduction =30-15=15

So firm 2 is reducing 15 units of pollution and firm 1 reducing 9 units of pollution.

As each firm have to reduce 12 units of pollution but firm 2 reducing 3 units more while firm 1 reducing 3 less units.

So, firm 2 is selling 3 units of pollution emission permit to firm 1.

F)firm 1 reduce 9 units and firm 2 reduce 12 units of pollution after trade.

Total cost of pollution reduction will total Benefit reduction by pollution reduction.

MB=112.5 -1.875E

TB=112.5E-0.9375E^2

TB at E=60

TB=112.5*60-0.9375*60*60=6750-3375=3375

TB at E=36

TB=112.5*36-0.9375*36*36=4050-1215=2836

Total cost of pollution reduction=3375-2836=540

G)price of permit= cost of extra pollution reduction by firm 2 or total cost from 9 to 12 by firm 2

MB=90-3E

TB=90E- 1.5E^2

TB at E=18

TB=90*18 -1.5*18*18=1620-486=1134

TB at E=15

TB=90*15 -1.5*15*15=1350-337.5=1012.5

Permit price=1134-1012.5=121.5

Total cost to firm 2 =1134

Net total cost to firm 2=1134-121.5=1012.5

Total cost to firm 1=150E-2.5E^2=150*9-2.5*9*9=1350-202.5=1147.5

Net total cost=1147.5+121.5=1269

H) the total cost is lower in cap & trade policy is because the firm who has higher cost of pollution reduction is paying the other firm who has lower cost of pollution reduction to reduce more pollution ,so that his part of pollution reduction can be completed.

And the amount he is paying is equal to the amount that is cost of other firm of reducing additional pollution units.

So the cost the firm is lower as he is paying lower amount than if he reduce pollution by itself.

5 0
3 years ago
May someone help me with these questions it is only 2
garri49 [273]
Most likely decreased birth rate and increased emigration.
6 0
3 years ago
The neutrons within the nucleus of an atom have what charge?
vivado [14]

Answer:

the answer is D.

Explanation:

your welcome :)

4 0
2 years ago
When 9.36 g sodium hydroxide is dissolved in enough water to make a total volume of 965 mL, what is the concentration of the res
SSSSS [86.1K]

Answer:

0.2425 M

Explanation:

Given mass = 9.36 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{9.36\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 0.234\ mol

Given that:- Volume = 965 mL = 0.965 L ( 1 mL = 0.001 L )

So,

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.234\ mol}{0.965\ L}=0.2425\ M

5 0
3 years ago
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If A and B have the SAME mass. A floats and B sinks. B MUST have a
Alexandra [31]

Answer:

volume

Explanation:

6 0
3 years ago
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