1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AURORKA [14]
2 years ago
10

How was Earth’s atmosphere changed during the Great Oxygenation Event?

Chemistry
2 answers:
SpyIntel [72]2 years ago
8 0

Consequences of oxygenation. Eventually, oxygen started to accumulate in the atmosphere, with two major consequences. Oxygen likely oxidized atmospheric methane (a strong greenhouse gas) to carbon dioxide (a weaker one) and water.

faust18 [17]2 years ago
3 0

Answer: .Early organisms created oxygen from other gases in the atmosphere

Explanation:

It is believed that the atmosphere emerged about 4,500 million years ago, by a process that can be explained in five stages.

In the first stage, the atmosphere was shaped by volcanic emanations, such as water vapor, carbon and sulfur dioxide, and nitrogen. At this point, oxygen was barely present.

In the second stage, as the Earth cooled, the water vapor condensed and formed the oceans. Carbon dioxide reacted with the rocks of the earth's crust to create carbonates - (CO32-); a portion of them, when dissolved in the seas, generated salt water.

In the third stage, approximately 3.500 million years ago, bacteria appear, capable of carrying out photosynthesis, that is, of producing oxygen. This facilitated the development of marine life.

Once the atmosphere obtained sufficient oxygen, the fourth stage appeared, the evolution of large organisms as animals capable of breathing air.

This is how the current atmosphere containing the gases created in each of the previous phases was reached. These are kept in motion by winds and rains, allowing humans, and other living organisms, to breathe. For this reason, without them there would be no life on the planet.

You might be interested in
What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?
Phantasy [73]

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole

Also number of moles is not given so applying the formula

n= mass ÷ molar mass of one mole of the gas.

n = m ÷ x   ( x  molar mass) ( m mass given)

Now putting the values in Ideal Gas Law equation

PV = m ÷ x RT

3.29 × 4.60 = 37.96/x × 0.08206 × 375

15.134 = 1168.1241  ÷ x

15.134x = 1168.1241

x = 1168.1241 ÷ 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.

8 0
3 years ago
What is thermal equilibrium? equal temperature equal heat equal thermal energy equal conductivity
Margarita [4]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

I believe the answer would be A. equal temperature

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

6 0
3 years ago
Read 2 more answers
How is the use of word theory in science different from its more common use
weqwewe [10]
It is like an idea that they come up with in an experimeant

4 0
3 years ago
What is the solution to the problem expressed to the correct number of significant figures
quester [9]

I don't know what the problem is, but here are some rues to help you out:

  1. All non-zero figures are significant
  2. When a zero falls between non-zero digits, that zero is significant.
  3. When a zero falls after a decimal point, that zero is significant.
  4. When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
  5. When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.
4 0
3 years ago
Rhodium-101 has a half life of 3.3 years. What percent of the sample will remain after 6.6 years?
babunello [35]

Answer:

25%

Explanation:

Half life means that 50% of the sample is gone at 3.3 years. This means that an additional 3.3 years (total 6.6 years) will reduce the sample a further 50% from the point at 3.3 years. In numbers, this means 50% of 50% (0.50*0.50), which is 25%.

5 0
3 years ago
Other questions:
  • At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?
    8·2 answers
  • Uranium has 146 neutrons; therefore its mass number is which of the following?
    12·2 answers
  • COMPARE AND CONTRAST <br> PROPANE AND HEXANE ...?
    15·1 answer
  • Cryosphere definition earth science
    11·2 answers
  • How many moles of oxygen gas would be needed to react completely with 8 moles of lithium metal in the following reaction? 4Li +
    15·1 answer
  • What happens to the entropy in the reaction I^2(s) ►I^2(g)?
    10·1 answer
  • A _____ is a new substance formed in a chemical reaction.
    8·1 answer
  • Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrate
    7·1 answer
  • Which salt is not formed from metal ions. NaCl, BaSO4, SrCl2, NH4OH
    6·2 answers
  • SOME ONE HEEEEELLLLPPPPPPPP PLEAAASEEE
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!