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OverLord2011 [107]
4 years ago
8

The fractional_part function divides the numerator by the denominator, and returns just the fractional part (a number between 0

and 1). Complete the body of the function so that it returns the right number. Note: Since division by 0 produces an error, if the denominator is 0, the function should return 0 instead of attempting the division. 1 point  1 2  3 4 5 6 7 8 9 10 11 def fractional_part(numerator, denominator): # Operate with numerator and denominator to # keep just the fractional part of the quotient return 0 print(fractional_part(5, 5)) # Should be 0 print(fractional_part(5, 4)) # Should be 0.25 print(fractional_part(5, 3)) # Should be 0.66... print(fractional_part(5, 2)) # Should be 0.5 print(fractional_part(5, 0)) # Should be 0 print(fractional_part(0, 5)) # Should be 0
Computers and Technology
1 answer:
7nadin3 [17]4 years ago
7 0

Answer:

part a

Explanation:

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Int[] myArray1= new int[24]; int[] myArray2= new int[10]; float[] myArray3= new float[8]; int index1, index =0 for(int index1 =0
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Answer:

The value of myArray2[index2] when index1 = 12 is 30

Explanation:

In the source code, the formula for myArray2[index2] is;

   myArray2[index2] = index2 + index3 + myArray1[index1],

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When index1 increases to 12 in the for-loop statement, the "myArray1[index1]" is equal to 24, index2 is equal to 2 and index3 is 4. The total sum is equal to 30 and assigned to "myArray2[index2]".

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The CEO, calls you into her office and tells you that she's learned that the company needs a database to keep track of supplier
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3 years ago
Convert the following numbers. (Please show all steps; no marks will be awarded if no steps are shown) [1.5 x 4 = 6 marks]
katen-ka-za [31]

Answer:

i. 10210212

ii. 100 101 001 in BASE 2

iii. 46.4631

iv. 12.453125

Explanation:

i. Converting to base 10 we get

=  10 x 162 + 13 x 161 + 9 x 160 = 2777

Converting to base 10 we get  =

2777/3 = 925 with remainder 2

925/3 = 308 with remainder 1

308/3 = 102 with remainder 2

102/3 = 34 with remainder 0

34/3 = 11 with remainder 1

11/3 = 3 with remainder 2

3/3 = 1 with remainder 0

1/3 = 0 with remainder 1

Hence the Answer is 10210212

ii. = Octal is taken in pair of 3 bits , Writing binary of each number in 3 bits we get  = 100 101 001 in BASE 2

iii. = 1 x 52 + 2 x 51 + 3 x 50 + 3 x 5-1   = 38.6 in decimal

Converting to Octal we get

38 /8 = 4 with remainder 6

4 /8 = 0 with remainder 4

.6 x 8 =  4.8

.8 x 8 = 6.4

46.4631

iv. = 1x 81 + 4 x 80 + 3 x 8-1 + 5 x 8-2   = 12.453125

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Answer:

Sorting tools allow you to organize data into columns and rows that help you locate what you are looking for.

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