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nikdorinn [45]
3 years ago
14

The picture has the question on it

Computers and Technology
1 answer:
Bingel [31]3 years ago
4 0

The answer is B. Row

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Mrac [35]
<span>A _superkey___ is any key that uniquely identifies each row.</span>
6 0
3 years ago
Pa sagot po TLE-10<br>need den po Ng solution thank you​
horsena [70]

Answer:

HAHHAHAHA HAAHA g abbabanjaja abunjing <em><u>abunjin</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em>

3 0
2 years ago
I need to create a method named "root positive". which will either print the square root of the number passed to it or if the nu
rjkz [21]

Answer:

Explanation:

The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter a number of type double to calculate square root:");

       double num = in.nextDouble();

       rootPositive(num);

   }

   public static void rootPositive(double num) {

       if (num > 0) {

           System.out.println(Math.sqrt(num));

       } else {

           System.out.println("Number must not be negative.");

       }

   }

}

5 0
3 years ago
Write a program that prompts the user to enter a series of numbers between 0 and 10 asintegers. The user will enter all numbers
Anna71 [15]

Answer:

The program in Python is as follows:

import collections

from collections import Counter

from itertools import groupby

import statistics

str_input = input("Enter a series of numbers separated by space: ")

num_input = str_input.split(" ")

numList = []

for num in num_input:

         if(num.lstrip('-').isdigit()):

                   if num[0] == "-" or int(num)>10:

                             print(num," is out of bound - rejecting")

                   else:

                             print(num," is valid - accepting")

                             numList.append(int(num))

         else:

                   print(num," is not a number")

print("Largest number: ",max(numList))

print("Smallest number: ",min(numList))

print("Range: ",(max(numList) - min(numList)))

print("Mode: ",end = " ")

freqs = groupby(Counter(numList).most_common(), lambda x:x[1])

print([val for val,count in next(freqs)[1]])

count_freq = {}

count_freq = collections.Counter(numList)

for item in count_freq:

         print(item, end = " ")

         lent= int(count_freq[item])

         for i in range(lent):

                   print("#",end=" ")

print()

Explanation:

See attachment for program source file where comments are used as explanation. (Lines that begin with # are comments)

The frequency polygon is printed using #'s to represent the frequency of each list element

7 0
2 years ago
Write a Python function LetterGame() that repeatedly asks the user to input a letter. The function is to count the number of vow
kotegsom [21]

Answer:

def LetterGame():

   vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]

   count1 = count2 = 0

   while True:

       choice = input("Enter a letter / digit to stop: ")

       if choice.isdigit():

           break

       elif choice.isalpha():

           count1 += 1

           if choice in vowels:

               count2 += 1

   print("You entered " + str(count1) + " letters, " + str(count2) + " of which weere vowels.")

   print("The percentage of vowels was " + str(count2 / count1 * 100) + "%")

LetterGame()

Explanation:

Create a function called LetterGame

Inside the function:

Create a list of vowels

Initialize count1, counts the total letters, and count2, counts the vowels

Initialize a while loop that iterates until the specified condition is met in the loop

Get the input from the user. If it is a digit, stop the loop. If it is an alphabet, increase the count1 by 1, and also check if it is a vowel. If it is a vowel, increment the count2 by 1

When the loop is done, print the required information

Finally, call the function

4 0
3 years ago
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