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meriva
2 years ago
9

This scale drawing shows an enlargement in a figure.What is the value of x? Enter your answer as a decimal in the box.

Mathematics
1 answer:
densk [106]2 years ago
8 0
Let’s find the scale factor (the number each number on the left has been multiplied by)
14/10 = 1.4
The scale factor is 1.4 so 10 has been multiplied by 1.4 to get 14

so you are now going to do 1.4 * 4 = 5.6

5.6 is your answer!!
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A long year end status report for work is 136 pages long. You need to print 19 copies for a meeting next week. How much is the p
tatyana61 [14]

Answer:

$19.60

Step-by-step explanation:

Given data

number of pages= 136 pages

number of copies = 19 copies

Hence 19 copies make a total of = 136*19

=2584 pages

hence if 500 pages cost $3.80

  then   2584 pages will cost x

cross multiply

500x= 2584*3.8

500x=9819.2

Divide both sides by 500

x= 9819.2/500

x= 19.6384

x=$19.60

It will cost $19.60

3 0
3 years ago
PLEASE HELP ME!
9966 [12]

Answer:

it's C

Step-by-step explanation:


5 0
2 years ago
Read 2 more answers
If Bob The Baker can bake 12 pies in 8 hours, how many pies can he bake in a day (Hint: How many hours are in a day?
shusha [124]
He can make 36 pies in a day because there are 24 hours in a day and
24/8=3
3•12=36
6 0
2 years ago
If x = 2 calculate the value of x squared- x
monitta
Plug the x value which is 2 back to the x and solve.

I gave you two answers because I wasn’t sure if the question was (x^2) - 2 or x^2-2.
Those two functions look similar but is totally different so keep that in mind.

Hope you have a victorious day!

4 0
2 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
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