The highest frequency sound to which the machine can be adjusted is :
<u>Given data :</u>
Pressure = 10 Pa
Speed of sound = 344 m/s
Displacement altitude = 10⁻⁶ m
<h3>Determine the highest frequency sound ( f ) </h3>
applying the formula below
Pmax =
--- ( 1 )
Therefore :
f = ( Pmax * V ) / 
= ( 10 * 344 ) / 2
* 1.31 * 10⁵ * 10⁻⁶
= 4179.33 Hz
Hence we can conclude that The highest frequency sound to which the machine can be adjusted is : 4179.33 Hz .
Learn more about Frequency : brainly.com/question/25650657
<u><em>Attached below is the missing part of the question </em></u>
<em>A loud factory machine produces sound having a displacement amplitude in air of 1.00 μm, but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maximum pressure amplitude of the sound waves is limited to 10.0 Pa. Under the conditions of this factory, the bulk modulus of air is 1.31×105 Pa. The speed of sound in air is 344 m/s. What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit?</em>
The "D) People perceive objects as a whole" statement best describes an abductive reasoning. The abductive reasoning often has incomplete information as the base of its reasoning and the conclusion for this type of reasoning is not absolute. There will always be additional pieces of evidence and factors that could change the conclusion of this reasoning. Therefore<span> D statement is the most suitable answer.</span>
<h2>The gravitational potential energy is double for stone with twice the mass of other stone.</h2>
Explanation:
Let mass of stone 1 be m.
Mass of stone 2 is twice the mass of stone 1.
Mass of stone 2 = 2m
We know that
Gravitational potential energy = Mass x acceleration due to gravity x Height
PE = mgh
For stone 1 ,
PE₁ = mgh
For stone 2 ,
PE₂ = 2mgh = 2 PE₁
So the gravitational potential energy is double for stone with twice the mass of other stone.
Because the object hovering over the magnet is the same magnetic pole.