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Licemer1 [7]
3 years ago
15

Two stones, one with twice the mass of the other, are thrown straight up and rise to the same height h. Compare their changes in

gravitational potential energy.
Physics
2 answers:
Lady bird [3.3K]3 years ago
4 0
<h2>The gravitational potential energy is double for stone with twice the mass of other stone.</h2>

Explanation:

Let mass of stone 1 be m.

Mass of stone 2 is twice the mass of stone 1.

Mass of stone 2 = 2m

We know that

  Gravitational potential energy = Mass x acceleration due to gravity x Height

  PE = mgh

For stone 1 ,

                PE₁ = mgh

For stone 2 ,

                PE₂ = 2mgh = 2 PE₁

So the gravitational potential energy is double for stone with twice the mass of other stone.

               

Luba_88 [7]3 years ago
4 0

Answer:

 P.E₂ =  2 P.E₁

Explanation:

mass of stone 1 , m₁= m

mass of stone 2, m₂ = 2 m

rise of stone 1,  h₁ = h

rise of stone 2,  h₂ = h

Potential energy of the stone 1

P.E₁ = m₁ g h₁

P.E₁ = m g h

Potential energy of stone 2

 P.E₂ = m₂ g h₂

 P.E₂ =  2 m g h

now,

 P.E₂ =  2 P.E₁

Potential energy of the stone 2 is twice potential energy of the stone 1.

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9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o
Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).

Now the force of friction is F_s=\mu*N, where N is the normal force and from the diagram it is F_y=mg*cos(\theta).

Thus F_s=\mu*N=\mu*mg*cos(\theta).

Therefore,

F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).

Substituting the value for F_H,m,\mu, and \:\theta we get:

F_{tot}= -38.63N.

Now acceleration is simply

a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.

The negative sign indicates that the acceleration is directed up the incline.

Part B:

d=\frac{1}{2} at^2

Which can be rearranged to solve for t:

t=\sqrt{\frac{2d}{a} }

Substitute the value of d=0.50m and a=7.7m/s and we get:

t=0.36s.

which is our answer.

Notice that in using the formula to calculate time we used the positive value of a, because for this formula absolute value is needed.

5 0
4 years ago
An 80.0 kg skier slides down a hill shaped as shown. Assume
umka21 [38]

The height above the ground from where the skier start is 11.5 m.

<h3>Conservation of energy</h3>

The height above the ground from where the skier start is determined by applying the principle of conservation of energy as shown below;

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

h = \frac{v^2}{2g} \\\\h = \frac{15^2}{2 \times 9.8} \\\\h = 11.5 \ m

Thus, the height above the ground from where the skier start is 11.5 m.

Learn more about conservation of energy here: brainly.com/question/166559

8 0
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