Answer:
true ............................................
Answer:
Explanation:
No, the reading is not expected to be accurate. This is because Relative to Earth, the air on Mars is extremely thin. The Martian atmosphere is primarily carbon dioxide with a much lower surface pressure, and Mars does not have oceans and an Earthlike hydrological cycle so latent heat release is not as important as it is for Earth.
It takes work to push charge through a change of potential.
There's no change of potential along an equipotential path,
so that path doesn't require any work.
Answer:
0,93 atm
Explanation:
For this we will use PV = nRT
P is what we want to find
V = 1 L
n = 
= 0,038 moles
R = 0,082 
T = 25°C = 298,15 K
P * 1 = 0,038 *0,082 * 298,15
P = 0,93 atm
Do you mean ‘Does a larger object have less attraction than a smaller object?’ If so, then the answer is objects with a larger mass exert more attraction while objects with a smaller mass have less attraction.
