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IgorC [24]
3 years ago
14

A rotating lawn sprinkler sprays water in a circular area of grass. the Diameter of the grass shown is 10 feet. What is the area

of the grass covered by the sprinkler water?
Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer:

The area of the grass covered by the sprinkler water is approximately 78.54 feet^2

dedylja [7]3 years ago
3 0

Answer:

78.54 feet

Step-by-step explanation:

10 is the diameter so 5 is the radius,

A = πr2 = π·52 ≈ 78.53982

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ycow [4]

Answer:-3x+12

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Look at the graph below and answer the following.
bearhunter [10]

Answer:

Part 1) The graph has three (3) x-intercepts and  has one (1) y-intercept

Part 2) The y-value of the minimum point is -3

Part 3) f(4)=3

Part 4) f(0)=3

Part 5) f(5)=1.5

Part 6) x=-6

Part 7) The horizontal line y=-1 intersects the graph three times

Part 8) The value of the function for f(6) is equal to zero

Part 9) The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) The function is positive on the interval (-3,6) and (10,11) and is negative on the interval (-6,-3) and (6,10)

Step-by-step explanation:

Part 1) Find the number of x-intercepts and y-intercepts of the graph

we know that

The<u> x-intercepts</u> are the values of x when the value of y (the function) is equal to zero

Look at the graph

The graph has 3 x-intercepts

The x-intercepts are the points (-3,0), (6,0) and (10,0)

The<u> y-intercepts</u> are the values of y when the value of x is equal to zero

Look at the graph            

The graph has 1 y-intercept

The y-intercept is the point (0,3)

Part 2) The y value of the minimum point on the graph is?

we know that

Look at the picture

The minimum point is (-6,-3)

therefore

The y-value of the minimum point is -3

Part 3)  f(4) is equal to?

we know that

f(4) is the value of the function when the value of x is equal to 4

Look at the graph

For x=4

The value of the function is equal to y=3

therefore

f(4)=3

Part 4) f(0) is equal to?

we know that

f(0) is the value of the function when the value of x is equal to 0

Look at the graph

For x=0

The value of the function is equal to y=3

therefore

f(0)=3

Part 5) f(5) is equal to?

we know that

f(5) is the value of the function when the value of x is equal to 5

Look at the graph

For x=5

The value of the function is about y=1.5  (see the attached figure)

therefore

f(5)=1.5

Part 6) The value of x when f(x)= -3 is?

Look at the graph

we have the point (-6,-3)

when the value of f(x)=-3

the value of x is equal to x=-6

Part 7) The horizontal line y = -1 intersects the graph _____ times?

Look at the graph

The horizontal line y=-1 intersects the graph three times (see the attached figure)

Part 8) f(6) is positive or negative?

Look at the graph

we have the point (6,0)

For x=6

The value of the function is equal to zero

Part 9) Is the graph increasing or decreasing on the interval -6?

Look at the graph

The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) Is the graph positive or negative on the interval 6

Look at the graph

The function is positive (f(x) > 0) on the interval (-3,6) and (10,11) and is negative (f(x) < 0) on the interval (-6,-3) and (6,10)

4 0
3 years ago
PLZ HELP ASAP!!!!!!!!!!!!!!!!!
eimsori [14]
B and C because both bases are squares
8 0
3 years ago
Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the
olasank [31]

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

5 0
2 years ago
On a coordinate plane, a line is drawn from point a to point b. point a is at (negative 8, negative 13) and point b is at (4, 11
vladimir2022 [97]

The coordinate for point P which is one-third the length of the line segment from a to b is (-4, -5)

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Point a is at (-8, -13) and point b is at (4, 11). Hence the coordinates for point p(x, y) which is one-third the length of the line segment from a to b is:

x=\frac{1}{3}(4-(-8))+(-8)=-4\\ \\y=\frac{1}{3}(11-(-13))+(-13)=-5

The coordinate for point P which is one-third the length of the line segment from a to b is (-4, -5)

Find out more on equation at: brainly.com/question/2972832

#SPJ4

7 0
2 years ago
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