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IgorC [24]
3 years ago
14

A rotating lawn sprinkler sprays water in a circular area of grass. the Diameter of the grass shown is 10 feet. What is the area

of the grass covered by the sprinkler water?
Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer:

The area of the grass covered by the sprinkler water is approximately 78.54 feet^2

dedylja [7]3 years ago
3 0

Answer:

78.54 feet

Step-by-step explanation:

10 is the diameter so 5 is the radius,

A = πr2 = π·52 ≈ 78.53982

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Noah is standing 5 feet from a tree that is 12 feet tall. If Noah is looking at
Anastaziya [24]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
△DEF is shown below.<br><br>Triangle DEF<br><br>What is m∠DEF?​
S_A_V [24]

Answer:

m∠DEF = 50

Step-by-step explanation:

∠DEG = ∠GEF

3y + 4 = 5y - 10

subtract 4 from both sides

3y = 5y - 14

subtract 5y from both sides

-2y = -14

divide by -2

y = 7

Add 7 into the equations:

3y + 4 + 5y - 10

3(7) + 4 + 5(7) - 10

21 + 4 + 35 - 10

25 + 25

50

4 0
3 years ago
Find the surface area of the triangular prism. The base of the
alukav5142 [94]

Answer:

Step-by-step explanation:

6 0
3 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
F(x)=x^2-2x-7 <br> given the polynomial function find f(-5)
UkoKoshka [18]

Answer:

f(-5)=28

Step-by-step explanation:

f(x)=x²-2x-7

f(-5) means that we have to replace x by -5.

f(-5)=(-5)²-2(-5)-7=25+10-7=25+3=28

4 0
3 years ago
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