Compare the three types of friction

Lightning flashes one mile (1609 m) away from you. How much time does it take the light to travel that distance?

hichkok12 [17]

Answer:

$t=5.36\times 10^{-6}\ s$

Explanation:

Given that,

Lightning flashes one mile (1609 m) away from you.

We need to find the time it take the light to travel that distance. Let the time be t. We know that,

speed = distance/time

$t=\dfrac{d}{v}\\\\t=\dfrac{1609}{3\cdot10^{8}}\\\\=5.36\times 10^{-6}\ s$

So, the required time is $5.36\times 10^{-6}\ s$

7 0

3 years ago

If energy is continually added to a gas, what will it likely become?

tamaranim1 [39]

The gas will remain a gas and the energy will be transformed into heat raising the temperature
(Some very rare exceptions might occur)

5 0

3 years ago

"A proton is placed in a uniform electric field of 2750 N/C. You may want to review (Page) . For related problem-solving tips an

tekilochka [14]

To solve this problem we will start from the definition of Force, as the product between the electric field and the proton charge. Once the force is found, it will be possible to apply Newton's second law, and find the proton acceleration, knowing its mass. Finally, through the linear motion kinematic equation we will find the speed of the proton.

PART A ) For the electrostatic force we have that is equal to

$F=qE$

Here

q= Charge

E = Electric Force

$F=(1.6*10^{-19}C)(2750N/C)$

$F = 4.4*10^{-16}N$

PART B) Rearrange the expression F=ma for the acceleration

$a = \frac{F}{m}$

Here,

a = Acceleration

F = Force

m = Mass

Replacing,

$a = \frac{4.4*10^{-16}N}{1.67*10^{-27}kg}$

$a = 2.635*10^{11}m/s^2$

PART C) Acceleration can be described as the speed change in an instant of time,

$a = \frac{v_f-v_i}{t}$

There is not $v_i$ then

$a = \frac{v_f}{t}$

Rearranging to find the velocity,

$v_f = at$

$v_f = (2.635*10^{11})(1.4*10^{-6})$

$v_f = 3.689*10^{5}m/s$

7 0

3 years ago

Measure the width of a sheet of a standard-sized (8.5in x 11.0in) loose-leaf notebook paper. Make the measurement in centimeters

laiz [17]

Answer: width = 27.94 cm

Explanation:

Given a sheet of a standard-sized (8.5in x 11.0in) loose-leaf notebook paper.

From the value given, the width is 11.0 inches

To make the measurement in centimeters, we will convert inches into centimeters.

1 inche = 2.54 centimeters

That is, 11 × 2.54 centimeters = 27.94 cm.

Therefore, the width is 27.94 cm.

3 0

4 years ago

Two point charges, q1 = 2.0 × 10−7 C and q2 = −6.0 × 10−8 C, are held 25.0 cm apart. (a) What is the electric field at a point 5

AlladinOne [14]

Answer:

a) $432000\frac{N}{C}\hat{i}$

b) $-6.92\times10^{-14}N\hat{i}$

Explanation:

a)

The magnitude of the electric field generated by a charged particle at a distance r is:

$E= k\frac{|Q|}{r^{2}}$

With Q the charge of the particle and k the constant ()

So, the electric field generated by q1 knowing that the point 5.0 cm apart the negative charge is $25.0cm-5.0cm=20.0 cm=0.2m$ apart the positive charge is:

$E_1= k\frac{|q1|}{r_1^{2}} =(9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}})\frac{|2.0\times10^{-7}|}{(0.2)^{2}}$

$E_1= 45000\frac{N}{C}$

and the electric field generated by q2:

$E_2= k\frac{|q2|}{r_2^{2}} =(9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}})\frac{|-6.0\times10^{-8}|}{(0.05)^{2}}$

$E_2=216000\frac{N}{C}$

Those are the magnitudes of the electric field, but electric field is a vector quantity, so the direction is important. Electric field generated by negative particles points towards the charge and electric field generated by positive particles points away the particle. So, if we define positive direction towards negative particle (x-axis):

$\overrightarrow{E_2}=+216000\frac{N}{C}\hat{i}$

$\overrightarrow{E_1}= +45000\frac{N}{C}\hat{i}$

Vector quantities satisfy superposition principle, this is $\overrightarrow{E}=\overrightarrow{E_1}+\overrightarrow{E_2}$ , with E the total electric field.

$\overrightarrow{E}=(216000+45000)\hat{i}=432000\frac{N}{C}\hat{i}$

b) The force is:

$\overrightarrow{F}=e*\overrightarrow{E}$ ,

with q the charge of an electron

$\overrightarrow{F}=(-1.61\times10^{-19})*(432000)\hat{i}=-6.92\times10^{-14}N\hat{i}$

8 0

3 years ago