Answer:
1 eV = 1.60 * 10^-19 J work done in accelerating electron thru 1 V
KE (total energy) = 1350 ^ 1 eV (note proton goes from + to -)
KE = 1.60 * 10^-19 * 1350 = 2.16 * 10^-16 Joules
1/2 m v^2 = KE = 2.16 * 10^-16 J
v^2 = 4.32 * 10E-16 / 1.67 * 10-27 = 2.59 * 10^11
v = 5.09 * 10^5 m/s
1) Inversely
2) increases
3) Boyle's
4) mass
5) Kelvin
6) Charles's
7) Gay-Lussac's
8) directly
9) combined
10) the amount
<span>The pressure and volume of a fixed mass of gas are inversely related. If one decreases, the other increases. This relationship is known as Boyle's law. The volume of a fixed mass of a gas is directly proportional to its kelvin temperature. This relationship is known as Charles's law. Gay-Lussac's law states that the pressure of a gas is directly proportional to the kelvin temperature if the volume remains constant. These three separate gas laws can be written as a single expression called the combined gas law. It can be used in situations in which only the amount of gas is constant. </span>
Answer:
a)
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
the required distance is 40.98 m
Explanation:
Given that;
velocity of the river u = 1.70 m/s
velocity of boat v = 14.0 m/s
Now to get the velocity of the boat relative to shore;
( north of east), we say
a² + b² = c²
(1.70)² + (14.0)² = c²
2.89 + 196 = c²
198.89 = c²
c = √198.89
c = 14.1028 m/s
tan∅ = v/u = 14 / 1.7 = 8.23529
∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east
Therefore, the velocity of the boat relative to shore is;
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
width of river = 340 m,
ow far downstream has the boat moved by the time it reaches the north shore in meters = ?
we say;
340sin( 90° - 83.0765°)
⇒ 340sin( 6.9235°)
= 40.98 m
Therefore, the required distance is 40.98 m
Answer:
I believe the answer for #1 is D and the answer for #2 is B
Explanation:
I hope this is correct and helps
Answer:
The current would stop
Explanation:
Electric currents are interesting because they carry little to no momentum. As soon as you remove a power source, the whole current halts.
