An image that cannot be obtained on a screen is called an Virtual Image.
Answer:
v₀₂ = -2.67 m / s
Explanation:
Let's use the conservation of the moment, for this we define a system formed by the two cars.
Consider the north direction as positive and the subscript 1 will be used for car 1 and the subscript 2 for the second car
Initial instant. Before the crash
p₀ = -m₁ v₀₁ + m₂ v₀₂
Final moment. Right after the crash
p_f = (m₁ + m₂) v
p₀ = p_f
-m₁
+ m₂ v_{o2} = (m₁ + m2) v_{f}
v₀₂ =
+
let's calculate
v₀₂ =
v₀₂ = -2.67 m / s
the negative sign indicates that the carriage moves in the opposite direction of the temperies
The answer is C. Acceleration is nonzero, but it’s velocity is zero
The star that would be hotter would be; the star emitting visible light.