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3 years ago

-65=6b-11 hi I don't understand how to solve this equation can someone please explain :)

Mathematics

2 answers:

Anastasy [175]3 years ago

8 0

Answer:

-9

Step-by-step explanation:

-65 = 6b - 11

Here, we’re solving for the unknown which is b.

Add 11 to both sides to eliminate -11 on the right side

-65 + 11 = 6b - 11 + 11

-54 = 6b

Now divide both sides by 6 to isolate b

-54/6 = 6b/6

-9 = b

b = -9

belka [17]3 years ago

7 0

-65=6b-11

Add 11 to both sides to get rid of the -11 on the right side

-54=6b

Then divide both sides by six to find the value of b

-9=b

So b is -9

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2 years ago

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A photograph 5 inches wide by 6 inches high is to be enlarged so that the new height is 20 inches. what will the width of the en

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2 years ago

Select the correct answer. Rewrite the following expression.

kolezko [41]

The algebraic expression $x^{10/3}$ is equivalent to the algebraic expression $x^{3}\cdot \sqrt[3]{x}$ . Thus, the right choice is option D.

<h3>How to apply power and root properties to rewrite a given expression</h3>

In this question we must apply the following set of algebraic properties to simplify a given expression:

$x^{m/n} = \sqrt[n]{x^{m}} = \left(\sqrt[n]{x}\right)^{m}$ (1)

$x^{m+n} = x^{m}\cdot x^{n}$ (2)

$x^{m\cdot n} = \left(x^{m}\right)^{n} = \left(x^{n}\right)^{m}$ (3)

Where:

m, n - Exponents
x - Base

And also by apply the definition of power.

If we know that the given expression is $x^{10/3}$ , then the equivalent expression is:

$x^{10/3} = \sqrt[3]{x^{10}} = \sqrt[3]{x^{9}\cdot x} = \sqrt[3]{x^{9}}\cdot \sqrt[3]{x} = x^{3}\cdot \sqrt[3]{x}$

The algebraic expression $x^{10/3}$ is equivalent to the algebraic expression $x^{3}\cdot \sqrt[3]{x}$ . Thus, the right choice is option D.

To learn more on roots, we kindly invite to check this verified question: brainly.com/question/1527773

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2 years ago

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lorasvet [3.4K]

Answer:

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Step-by-step explanation:

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2 years ago