Rayville Elementary sponsors a math competition for 78 students. During the competition, the students work a total of 8,970 math
1 answer:
Each student worked on 115 math problems.
Step-by-step explanation:
Given,
Problems solved in 4 hours = 8970
Number of students in competition = 78
As each student solved same number of problems, we will divide the total problems solved by number of students to find the amount of problems solved by one student.
Problems solved by one student =
Problems solved by one student = 115
Each student worked on 115 math problems.
Keywords: division
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Step-by-step explanation:
Let a be the price of 1 adult ticket.
Let c be the price of 1 child ticket.
given,
as equation 1,
and
as equation 2.
Now we will solve for a and c using elimination method of simultaneous equations.
Now we multiply equation 2 by 2 to eliminate a and solve for c.
This new equation will be equation 3.
Now we will use equation 1 - equation 3 to eliminate a and solve for c.
Now substitute c into equation 2.
Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.