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Sphinxa [80]
2 years ago
13

PLEASE ANSWER THIS IT'S 30 POINTS

Mathematics
1 answer:
sergey [27]2 years ago
5 0

Answer:

Step-by-step explanation:

since we know that the 50 degrees is one side of the line then the angle that is strait opposite from this angle is 50 degrees, so 50+60=110degrees and 180-110=70, so x=70 degrees

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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
Hailey is making 36 mini- pumpkin pies. Each pie takes 6 ounces of pumpkin. The cans of pumpkin are 2 pounds each. How many can
serious [3.7K]
1 pound = 16 ounces

6 ounces each pie

36 mini pies to make

36 × 6 = 216 ounces needed to make 36 mini pies

216 ÷ 16 = 13.5 pounds
if each can of pumpkin is 2 pounds,
13.5 ÷ 2 = 6.75 so that would be 7 cans of pumpkin
3 0
3 years ago
Which is the graph of the linear equation X=-2
tankabanditka [31]

Answer:

photomath thats what u should use or put it in a calculator

3 0
4 years ago
The ratio of blue crayons to red crayons in a classroom is 32:28. The classroom has 16 blue crayons.
AnnyKZ [126]
32/28=16/x
32x= 448
x=14
There are 14 red crayons in classroom
5 0
2 years ago
Read 2 more answers
Pls can you help me here PLSSSS. it would mean a lot for me.
VLD [36.1K]

Answer:

27.183m. squared

Step-by-step explanation:

Find the base, then find the volume

Base:

(2.6*4.1*0.5)=

(10.66*0.5)=

5.33

Volume:

(5.33*5.1)=

27.183

Hope that this helped!

8 0
3 years ago
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